Question

我必须创建一个程序，它计算X字母的频率/出现次数，我有程序计算单词的频率和长度，但现在我需要计算出的平均长度进入的话，我真的被困在这，所以如果有人可以帮助我将感激不尽

这是我迄今为止的代码：

import javax.swing.JOptionPane;
public class CountLetters {
public static void main( String[] args ) {
    String input = JOptionPane.showInputDialog("Write a sentence." );
    int amount = 0;
    String output = "Amount of letters:\n";

    for ( int i = 0; i < input.length(); i++ ) {
        char letter = input.charAt(i);
        amount++;
        output = input;
    }
    output += "\n" + amount;
    JOptionPane.showMessageDialog( null, output,
                         "Letters", JOptionPane.PLAIN_MESSAGE ); 
}
}

Answer 1

平均值只是totalValue / totalCount。

将其作为现有代码末尾的另一个循环：

从0开始。

long totalValue = 0;
long totalCount = 0;

所以你需要遍历所有的字数：

totalValue += wordLength * wordCount;
totalCount += wordCount;

然后在结束时你就做了：

float mean = (float)totalValue/totalCount;

或者，在执行主循环的同时计算平均值，您可以这样做：

totalValue += wordLength;
totalCount += 1;

一旦你找到一个单词，每次都围绕主循环。

Answer 2

使用地图将字长映射到字长发生的次数。

然后按照Tim B回答的乘法逻辑。

我拼凑的一个简单例子。

public static void main(final String[] args) {
        final Map<Integer, Integer> wordLengths = new HashMap<Integer, Integer>();

        final String testString = "the quick brown fox jumped over the lazy dog";
        final String[] words = testString.split(" ");

        for (int i = 0; i < words.length; i++) {
            final int wordLength = words[i].length();

            if( wordLengths.keySet().contains( wordLength ) ) {
                Integer currentNumberOfOccurences = wordLengths.get(wordLength);
                currentNumberOfOccurences++;
                wordLengths.put(wordLength, currentNumberOfOccurences);
                continue;
            }

            wordLengths.put(wordLength, 1);
        }

        double totalLength = 0;
        double totalOccurrences = 0;
        for (final Integer length : wordLengths.keySet()) {
            final Integer occurrences = wordLengths.get(length);
            totalLength = totalLength + (length * occurrences );
            totalOccurrences += occurrences;
        }

        final double mean = totalLength / totalOccurrences;

        System.out.println("Average word length is: " + mean );
    }

算上X字母的频率？

2 个答案: