Question

我目前有一个URL请求带回XML数据。我将该数据存储在读取的文档中，并查找某些属性之间的信息，并将这些值分配给我指定的变量。我的wpf DataGrid叫做Movie_DataGrid。如何将这些数据提供给DataGrid会有任何帮助。

- 编辑 -

我用一种新的方式更新了我的代码，我试图得到我的结果。当单步执行代码的每一步时，XML存储正常，并且Retrivalinfo类和Retrievalinfo convertedMovie = new Retrievalinfo（）之间的所有标记属性都相同，但是此方法的应用程序错误。

我的新问题是，属性中的值未被抓取和存储。我还提供了一些我会得到的XML样本。

<root response="True">
<movie title="Up in the Air" year="2009" rated="R" released="23 Dec 2009" runtime="109 
min" genre="Drama, Romance" director="Jason Reitman" writer="Walter Kirn (novel), Jason
Reitman (screenplay), Sheldon Turner (screenplay)" actors="George Clooney, Vera Farmiga,
Anna Kendrick, Jason Bateman" plot="With a job that has him traveling around the country
firing people, Ryan Bingham leads an empty life out of a suitcase, until his company
does the unexpected: ground him." language="English" country="USA" awards="Nominated for
6 Oscars. Another 64 wins & 66 nominations."poster="http://ia.mediaimdb.com/images/M/MV5BMTI3MzYxMTA4NF5BMl5BanBnXkFtZTcwMD
E4ODg3Mg@@._V1_SX300.jpg" metascore="83" imdbRating="7.5" imdbVotes="215,961" imdbID="tt1193138" type="movie"/>
</root>    


     // This action will seach the IMDb API for the associated infromation for the IMDBID that is tagged with the title you chose in the ListBox.
     private void Movie_List_SelectionChanged(object sender, SelectionChangedEventArgs e)
     {   // Grabs the IMDBID associated to the movie title selected to be used with the second API request.
        var p = Movie_List.SelectedIndex;

        string titleID = structholder[p].IMDBID;

        // Prepares 2nd API URL request to get data for chosen title.
        // Creates a XML Document  to store the xml data that was sent back by the API.
        XmlDocument doc = new XmlDocument();
        doc.Load("http://www.omdbapi.com/?i=" + titleID + "&r=XML");

        // Creates a XML Noedlist to store the values that are going to be associated with the given attribute tag.
        XmlNodeList movieList = doc.GetElementsByTagName("movie");

        var movie = movieList.Item(0);

        Retrievalinfo convertedMovie = new Retrievalinfo()
        {
            title = movie.Attributes["title"].ToString(),
            actors = movie.Attributes["actors"].ToString().Split(',').ToList(),
            genre = movie.Attributes["genre"].ToString(),
            rated = movie.Attributes["rated"].ToString(),
            imdbRating = movie.Attributes["imbdRating"].ToString(),
            released = movie.Attributes["released"].ToString(),
            runtime = movie.Attributes["runtime"].ToString(),
        };

        List<Retrievalinfo> gridInfo = new List<Retrievalinfo>();
        Movie_DataGrid.ItemsSource = gridInfo;

以下是我希望在DataGrid中显示每个变量的类。

namespace WpfApplication3
{
    public class Retrievalinfo
    {
       public Retrievalinfo()
        {
            actors = new List<string>();
        }

        //Creating a list of info objects that will store all returned data for selected title.
        public string title; 
        public List<string> actors; 
        public string genre;
        public string rated;
        public string imdbRating; 
        public string released; 
        public string runtime;

    }

    }

Answer 1

我虽然写了一个冗长的aswer但是，这里有一个快速的样本供你自己使用，作为参考并自己弄清楚细节。 MVVM不包括在内：D

希望它有所帮助。

<强>代码隐藏

namespace MyMovies
{
    public partial class MainWindow : Window
    {
        public MainWindow()
        {
            InitializeComponent();
            DataContext = this;

            Movies = new ObservableCollection<Movie>()
                {
                    new Movie("Lock, Stock and Two Smoking Barrels", 4),
                    new Movie("Life of Brian", 5),
                };

            var addMovieCommand = new RoutedUICommand();
            CommandManager.RegisterClassCommandBinding(typeof(Window),
                new CommandBinding(
                    addMovieCommand,
                    (sender, args) => AddMovie(),
                    (sender, args) => args.CanExecute = true));
            AddMovieCommand = addMovieCommand;
        }

        public ObservableCollection<Movie> Movies { get; set; }

        public ICommand AddMovieCommand { get; set; }

        private void AddMovie()
        {
            Movies.Add(new Movie(Guid.NewGuid().ToString(), 3));
        }
    }

    public class Movie
    {
        public Movie(string name, int stars)
        {
            Name = name;
            Stars = stars;
        }

        public string Name { get; set; }
        public int Stars { get; set; }
    }
}

<强> XAML

<Window x:Class="MyMovies.MainWindow"
        xmlns="http://schemas.microsoft.com/winfx/2006/xaml/presentation"
        xmlns:x="http://schemas.microsoft.com/winfx/2006/xaml"
        Title="MainWindow" Height="350" Width="525">
    <Grid>
        <StackPanel>
            <DataGrid 
                HorizontalAlignment="Stretch" 
                VerticalAlignment="Stretch"
                ItemsSource="{Binding Movies}">
            </DataGrid>
            <Button Content="Add movie" Command="{Binding AddMovieCommand}" />
        </StackPanel>
    </Grid>
</Window>

哪个给你

notfound

Answer 2

如果我正确理解你的问题，你需要一些：

视图模型中的ObservableCollection<RetrievalInfo>用于存储检索到的数据
XAML中的Datagrid（或者网格视图），其项目源绑定到上述属性
上述控件中的列表示您的每个数据片段。
检索代码应修改可观察集合，以便它们显示在您的UI上

我很乐意为您不确定如何实施的任何或所有部分提供样品。

Answer 3

您可以使用以下博客中提供的代码段读取xml到对象列表

博客链接：

http://danielwylie.me/blog/2010/04/c-convert-xml-to-an-object-or-list-of-an-object

您可以使用以下代码段

指定dataGrid的ItemSource

Movie_DataGrid.ItemsSource = list;
        //here list object from  public static List<T> XmlToObjectList<T>(string xml, string nodePath)  method

将数据绑定到数据网格

3 个答案: