Question

鉴于以下内容，我如何只在DeviceListBox中显示DeviceName属性？

namespace NotMyNS
{
    public class Device
    {
        public int SerialNumber { get; set; }
        public string DeviceName { get; set; }
    }
}

namepace MyNS
{    
    public partial class myControl : UserControl
    {
        public ObservableCollection<NotMyNS.Device> DeviceList { get; set; }
    }
}

<UserControl x:Class="MyNS.myControl"
             xmlns="http://schemas.microsoft.com/winfx/2006/xaml/presentation"
             xmlns:x="http://schemas.microsoft.com/winfx/2006/xaml"
             xmlns:mc="http://schemas.openxmlformats.org/markup-compatibility/2006" 
             xmlns:d="http://schemas.microsoft.com/expression/blend/2008"
             mc:Ignorable="d" 
             d:DesignHeight="300" d:DesignWidth="300">    
    <Grid >        
        <ListBox Name="DeviceListBox" />
    </Grid>
</UserControl>

我看了很多例子，但未能适应我所看到的问题。

Answer 1

您应该使用DisplayMemberPath：

<ListBox Name="DeviceListBox" ItemsSource="{Binding DeviceList}" DisplayMemberPath="DeviceName"  />

Answer 2

您可以将ItemsControl.DisplayMemberPath设置为要从视图模型中显示的属性。此外，如果您要将DeviceList用作ItemsSource，则需要将绑定上下文指定为UserControl

<ListBox 
   ItemsSource="{Binding RelativeSource={RelativeSource AncestorType={x:Type UserControl}}, Path=DeviceList}" 
   DisplayMemberPath="DeviceName" />

Answer 3

在这种情况下。您需要在DataTemplate内创建ListBox.ItemsSource。创建TextBlock并将其绑定到DeviceName。

Answer 4

您还必须设置DataContext。添加“DataContext = this;”到myControl构造函数。或者你可以这样做，而无需设置DataContext

<ListBox Name="DeviceListBox" ItemsSource="{Binding RelativeSource={RelativeSource
        FindAncestor,AncestorType={x:Type Window}},Path=DeviceList}" DisplayMemberPath="DeviceName"/>

非常简单地将对象列表绑定到ListBox

4 个答案: