我正在尝试使用Volley库与我的RESTful API进行通信。
当我要求持有者令牌时,我必须在正文中发布字符串。字符串应如下所示: grant_type =密码&安培;用户名=爱丽丝&安培;密码= password123 标题: 内容类型:application / x-www-form-urlencoded
有关WebApi个人账户的更多信息: http://www.asp.net/web-api/overview/security/individual-accounts-in-web-api
不幸的是我无法弄清楚如何解决它..
我正在尝试这样的事情:
StringRequest req = new StringRequest(Request.Method.POST, URL, new Response.Listener<String>() {
@Override
public void onResponse(String response) {
VolleyLog.v("Response:%n %s", response);
}
}, new Response.ErrorListener() {
@Override
public void onErrorResponse(VolleyError error) {
VolleyLog.e("Error: ", error.getMessage());
}
}){
@Override
protected Map<String, String> getParams() throws AuthFailureError {
Map<String, String> params = new HashMap<String, String>();
params.put("grant_type", "password");
params.put("username", "User0");
params.put("password", "Password0");
return params;
}
@Override
public Map<String, String> getHeaders() throws AuthFailureError {
Map<String, String> headers = new HashMap<String, String>();
headers.put("Content-Type", "application/x-www-form-urlencoded");
return headers;
}
};
我一直收到400 Bad Request。 我想我实际上是在发送这样的请求:
grant_type:password, username:User0, password:Password0
而不是:
grant_type=password&username=Alice&password=password123
如果有人有任何想法或建议,我将非常感激。
答案 0 :(得分:27)
要发送包含用户名和密码等参数的普通POST请求(无JSON),您通常会覆盖getParams()并传递参数映射:
public void HttpPOSTRequestWithParameters() {
RequestQueue queue = Volley.newRequestQueue(this);
String url = "http://www.somewebsite.com/login.asp";
StringRequest postRequest = new StringRequest(Request.Method.POST, url,
new Response.Listener<String>()
{
@Override
public void onResponse(String response) {
Log.d("Response", response);
}
},
new Response.ErrorListener()
{
@Override
public void onErrorResponse(VolleyError error) {
Log.d("ERROR","error => "+error.toString());
}
}
) {
// this is the relevant method
@Override
protected Map<String, String> getParams()
{
Map<String, String> params = new HashMap<String, String>();
params.put("grant_type", "password");
// volley will escape this for you
params.put("randomFieldFilledWithAwkwardCharacters", "{{%stuffToBe Escaped/");
params.put("username", "Alice");
params.put("password", "password123");
return params;
}
};
queue.add(postRequest);
}
要在Volley StringRequest中将任意字符串作为POST正文数据发送,您可以覆盖getBody()
public void HttpPOSTRequestWithArbitaryStringBody() {
RequestQueue queue = Volley.newRequestQueue(this);
String url = "http://www.somewebsite.com/login.asp";
StringRequest postRequest = new StringRequest(Request.Method.POST, url,
new Response.Listener<String>()
{
@Override
public void onResponse(String response) {
Log.d("Response", response);
}
},
new Response.ErrorListener()
{
@Override
public void onErrorResponse(VolleyError error) {
Log.d("ERROR","error => "+error.toString());
}
}
) {
// this is the relevant method
@Override
public byte[] getBody() throws AuthFailureError {
String httpPostBody="grant_type=password&username=Alice&password=password123";
// usually you'd have a field with some values you'd want to escape, you need to do it yourself if overriding getBody. here's how you do it
try {
httpPostBody=httpPostBody+"&randomFieldFilledWithAwkwardCharacters="+URLEncoder.encode("{{%stuffToBe Escaped/","UTF-8");
} catch (UnsupportedEncodingException exception) {
Log.e("ERROR", "exception", exception);
// return null and don't pass any POST string if you encounter encoding error
return null;
}
return httpPostBody.getBytes();
}
};
queue.add(postRequest);
}
另外,Volley文档不存在,StackOverflow答案的质量非常糟糕。不能相信像这样的例子的答案已经不存在了。
答案 1 :(得分:7)
首先,我建议您通过打印到日志或使用wirehark或fiddler等网络嗅探器来确切了解您要发送的内容。
试图将护身符放入体内怎么样?如果您仍然需要StringRequest
,则需要对其进行扩展并覆盖getBody()
方法(类似于JsonObjectRequest
)
答案 2 :(得分:3)
我知道这已经过时了,但我遇到了同样的问题,这里有一个更清晰的解决方案:How to send a POST request using volley with string body?