Question

后端开发人员在POST请求中提供了这些说明：

路线：{url} / {app_name / {controller} / {action}
控制器和动作应该是小型的。
API测试链接：http： * ** * ** * ** * ** * ***
请求应使用POST方法。
参数应通过请求内容主体（FormUrlEncodedContent）传递。
参数应为json格式。
参数是关键敏感的。

在协议中没有第5号经验，我搜索并以我的代码结束。

-(id)initWithURLString:(NSString *)URLString withHTTPMEthod:(NSString *)method withHTTPBody:(NSDictionary *)body {

    _URLString = URLString;
    HTTPMethod = method;
    HTTPBody = body;

    //set error message
    errorMessage = @"Can't connect to server at this moment. Try again later";
    errorTitle = @"Connection Error";

    return  self;
}


-(void)fireConnectionRequest {

    NSOperationQueue *mainQueue = [[NSOperationQueue alloc] init];
    [mainQueue setMaxConcurrentOperationCount:5];

    NSError *error = Nil;

    NSURL *url = [NSURL URLWithString:_URLString];
    NSMutableURLRequest *request = [[NSMutableURLRequest alloc] initWithURL:url];

    NSData *sendData = [NSJSONSerialization dataWithJSONObject:HTTPBody options:NSJSONWritingPrettyPrinted error:&error];
    [request setHTTPMethod:@"POST"];

    [request setValue:@"application/x-www-form-urlencoded" forHTTPHeaderField:@"Content-Type"];
    [request setValue:@"application/json" forHTTPHeaderField:@"Accept"];

    [request setHTTPBody: sendData];
    [NSURLConnection connectionWithRequest:request delegate:self];

    NSString *jsonString = [[NSString alloc]initWithData:sendData encoding:NSUTF8StringEncoding];


    //fire URL connectiion request
    [NSURLConnection sendAsynchronousRequest:request queue:mainQueue completionHandler:^(NSURLResponse *response, NSData *responseData, NSError *error) {

        //get the return message and transform to dictionary
        NSString *data = [[NSString alloc] initWithData:responseData encoding:NSUTF8StringEncoding];
        returnMessage = [NSJSONSerialization JSONObjectWithData: [data dataUsingEncoding:NSUTF8StringEncoding]
                                                        options: NSJSONReadingMutableContainers
                                                          error:&error];


        //check return message
        if (!error) {
            [delegate returnMessageForTag:self.tag];

        }
        else {
            [delegate returnErrorMessageForTag:self.tag];
        }

    }];

}

我传递一个格式化为JSON的字典。他同意我能够传递正确的数据。我能够连接到API，但是当我尝试发送数据进行注册时，它总是返回“FAILED”。连接没有问题，但我无法传输数据。

这里使用相同API的Android开发人员没有问题，但由于他不熟悉iOS，因此无法帮助我。

我错过了什么？

Answer 1

尝试使用此代码

目标C

NSString *post =[NSString stringWithFormat:@"AgencyId=1&UserId=1&Type=1&Date=%@&Time=%@&Coords=%@&Image=h32979`7~U@)01123737373773&SeverityLevel=2",strDateLocal,strDateTime,dict];
NSData *postData = [post dataUsingEncoding:NSASCIIStringEncoding allowLossyConversion:YES];
NSString *postLength = [NSString stringWithFormat:@"%d",[postData length]];
NSMutableURLRequest *request = [[[NSMutableURLRequest alloc] init] autorelease];
[request setURL:[NSURL URLWithString:[NSString stringWithFormat:@"http://google/places"]]];
[request setHTTPMethod:@"POST"];
[request setValue:postLength forHTTPHeaderField:@"Content-Length"];
[request setValue:@"application/x-www-form-urlencoded" forHTTPHeaderField:@"Content-Type"];
[request setHTTPBody:postData];
NSError *error;
NSURLResponse *response;
NSData *urlData=[NSURLConnection sendSynchronousRequest:request returningResponse:&response error:&error];
NSString *str=[[NSString alloc]initWithData:urlData encoding:NSUTF8StringEncoding];

Swift 2.2

var post = "AgencyId=1&UserId=1&Type=1&Date=\(strDateLocal)&Time=\(strDateTime)&Coords=\(dict)&Image=h32979`7~U@)01123737373773&SeverityLevel=2"
var postData = post.dataUsingEncoding(NSASCIIStringEncoding, allowLossyConversion: true)!
var postLength = "\(postData.length)"
var request = NSMutableURLRequest()
request.URL = NSURL(string: "http://google/places")!
request.HTTPMethod = "POST"
request.setValue(postLength, forHTTPHeaderField: "Content-Length")
request.setValue("application/x-www-form-urlencoded", forHTTPHeaderField: "Content-Type")
request.HTTPBody = postData
NSError * error
NSURLResponse * response
var urlData = try! NSURLConnection.sendSynchronousRequest(request, returningResponse: response)!
var str = String(data: urlData, encoding: NSUTF8StringEncoding)

Swift 3.0

let jsonData = try? JSONSerialization.data(withJSONObject: kParameters)
    let url: URL = URL(string: "Add Your API URL HERE")!
    print(url)
    var request: URLRequest = URLRequest(url: url)
    request.httpMethod = "POST"
    request.httpBody = jsonData
    request.setValue(Constant.UserDefaults.object(forKey: "Authorization") as! String?, forHTTPHeaderField: "Authorization")
    request.setValue(Constant.kAppContentType, forHTTPHeaderField: "Content-Type")
    request.setValue(Constant.UserAgentFormat(), forHTTPHeaderField: "User-Agent")

    let task = URLSession.shared.dataTask(with: request, completionHandler: { data, response, error in

        if data != nil {

            do {
                let json = try JSONSerialization.jsonObject(with: data!, options: .allowFragments) as! NSDictionary
                print(json)
            } catch let error as NSError {
                print(error)
            }
        } else {
            let emptyDict = NSDictionary()
        }
    })
    task.resume()

Swift 4

let headers = [
            "Content-Type": "application/x-www-form-urlencoded"
        ]

    let postData = NSMutableData(data: "UserID=351".data(using: String.Encoding.utf8)!)
    let request = NSMutableURLRequest(url: NSURL(string: "Add Your URL Here")! as URL,
                                      cachePolicy: .useProtocolCachePolicy,
                                      timeoutInterval: 10.0)
    request.httpMethod = "POST"
    request.allHTTPHeaderFields = headers
    request.httpBody = postData as Data

    let session = URLSession.shared
    let dataTask = session.dataTask(with: request as URLRequest, completionHandler: { (data, response, error) -> Void in
        if (error != nil) {
            print(error!)
        } else {
            let httpResponse = response as? HTTPURLResponse
            print(httpResponse!)

            do {
                let json = try JSONSerialization.jsonObject(with: data!, options: .allowFragments)
                print(json)
            } catch {
                print(error)
            }

        }
    })

    dataTask.resume()

<强> Alamofire

Alamofire.request("Add Your URL Here",method: .post, parameters: ["CategoryId": "15"])
        .validate(contentType: ["application/x-www-form-urlencoded"])
        .responseJSON { (response) in

            print(response.result.value)

    }

我希望这段代码对你有用。

Answer 2

@fatihyildizhan

没有足够的声誉直接评论你的答案，因此这个答案。

Swift 1.2

let myParams = "username=user1&password=12345"
let postData = myParams.dataUsingEncoding(NSASCIIStringEncoding, allowLossyConversion: true)
let postLength = String(format: "%d", postData!.length)

var myRequest = NSMutableURLRequest(URL: self.url)
myRequest.HTTPMethod = "POST"
myRequest.setValue(postLength, forHTTPHeaderField: "Content-Length")
myRequest.setValue("application/x-www-form-urlencoded", forHTTPHeaderField: "Content-Type")
myRequest.HTTPBody = postData

var response: AutoreleasingUnsafeMutablePointer<NSURLResponse?> = nil

以上代码在我的情况下运行正常。

Answer 3

快捷键4

let params = ["password":873311,"username":"jadon","client_id":"a793fb82-c978-11e9-a32f-2a2ae2dbcce4"]
let jsonString = params.reduce("") { "\($0)\($1.0)=\($1.1)&" }
let jsonData = jsonString.data(using: .utf8, allowLossyConversion: false)!
urlRequest.addValue("application/x-www-form-urlencoded", forHTTPHeaderField:"Content-Type")
urlRequest.httpBody  = jsonData

Answer 4

使用Swift 3，让jsonData =试试？ JSONSerialization.data（withJSONObject：kParameters）对我不起作用，所以我不得不复制AlamoFire解决方案......

let body2 = ["username": "au@gmail.com",
        "password": "111",
        "client_secret":"7E",
        "grant_type":"password"]

let data : Data = query(body2).data(using: .utf8, allowLossyConversion: false)!
var request : URLRequest = URLRequest(url: url)
request.httpMethod = "POST"
request.setValue("application/x-www-form-urlencoded", forHTTPHeaderField:"Content-Type");
request.setValue(NSLocalizedString("lang", comment: ""), forHTTPHeaderField:"Accept-Language");
request.httpBody = data 

do {...}

}

public func queryComponents(fromKey key: String, value: Any) -> [(String, String)] {
        var components: [(String, String)] = []

        if let dictionary = value as? [String: Any] {
            for (nestedKey, value) in dictionary {
                components += queryComponents(fromKey: "\(key)[\(nestedKey)]", value: value)
            }
        } else if let array = value as? [Any] {
            for value in array {
                components += queryComponents(fromKey: "\(key)[]", value: value)
            }
        } else if let value = value as? NSNumber {
            if value.isBool {
                components.append((escape(key), escape((value.boolValue ? "1" : "0"))))
            } else {
                components.append((escape(key), escape("\(value)")))
            }
        } else if let bool = value as? Bool {
            components.append((escape(key), escape((bool ? "1" : "0"))))
        } else {
            components.append((escape(key), escape("\(value)")))
        }

        return components
    }


    public func escape(_ string: String) -> String {
        let generalDelimitersToEncode = ":#[]@" // does not include "?" or "/" due to RFC 3986 - Section 3.4
        let subDelimitersToEncode = "!$&'()*+,;="

        var allowedCharacterSet = CharacterSet.urlQueryAllowed
        allowedCharacterSet.remove(charactersIn: "\(generalDelimitersToEncode)\(subDelimitersToEncode)")

        var escaped = ""

        if #available(iOS 8.3, *) {
            escaped = string.addingPercentEncoding(withAllowedCharacters: allowedCharacterSet) ?? string
        } else {
            let batchSize = 50
            var index = string.startIndex

            while index != string.endIndex {
                let startIndex = index
                let endIndex = string.index(index, offsetBy: batchSize, limitedBy: string.endIndex) ?? string.endIndex
                let range = startIndex..<endIndex

                let substring = string.substring(with: range)

                escaped += substring.addingPercentEncoding(withAllowedCharacters: allowedCharacterSet) ?? substring

                index = endIndex
            }
        }
        return escaped
    }

还有一个扩展名：

extension NSNumber {
fileprivate var isBool: Bool { return CFBooleanGetTypeID() == CFGetTypeID(self) }}

这是暂时的，它必须是更好的解决方案......

希望有所帮助...

Answer 5

Swift确实提供了用于URL％编码的功能，但是与@nolanw在第一条注释中指出的不完全匹配。对于原始问题的第5步，一旦您具有某种结构的键值对，以下是一种简短而简单的编码替代方法（Swift 4.2）：

var urlParser = URLComponents()
urlParser.queryItems = [
    URLQueryItem(name: "name", value: "Tim Tebow"),
    URLQueryItem(name: "desc", value: "Gators' QB")
]
let httpBodyString = urlParser.percentEncodedQuery

将其粘贴到Xcode游乐场中，然后添加print(httpBodyString!)。在输出中，您将看到：

name=Tim%20Tebow&desc=Gators'%20QB

注意：这是用于百分比编码的基本表单值集（即不是二进制数据也不是多部分）

Answer 6

是否可以将此代码转换为swift？我已经尝试但无法处理它。也许这个代码块可以帮助你。感谢。

    let myParams:NSString = "username=user1&password=12345"
    let myParamsNSData:NSData = NSData(base64EncodedString: myParams, options: NSDataBase64DecodingOptions.IgnoreUnknownCharacters)!
    let myParamsLength:NSString = NSString(UTF8String: myParamsNSData.length)
    let myRequest: NSMutableURLRequest = NSURL(fileURLWithPath: self.url)
    myRequest.HTTPMethod = "POST"
    myRequest.addValue("application/x-www-form-urlencoded", forHTTPHeaderField: "Content-Type")
    myRequest.HTTPBody = myParamsNSData
    var data2: NSData!
    var error2: NSError!

Answer 7

Swift 4.2

    func percentEscapeString(_ string: String) -> String {
            var characterSet = CharacterSet.alphanumerics
            characterSet.insert(charactersIn: "-._* ")
            return string
              .addingPercentEncoding(withAllowedCharacters: characterSet)!
              .replacingOccurrences(of: " ", with: " ")
              .replacingOccurrences(of: " ", with: " ", options: [], range: nil)
              .replacingOccurrences(of: "\"", with: "", options: NSString.CompareOptions.literal, range:nil)
          }
//    Set encoded values to Dict values you can decode keys if required
    dictData.forEach { (key, value) in
              if let val = value as? String {
                dictData[key] = self.percentEscapeString(val)
              } else {
                dictData[key] = value
              }
            }

这对我有用，这是来源https://gist.github.com/HomerJSimpson/80c95f0424b8e9718a40

的链接

Answer 8

将字典参数解析为字符串：

-(NSData *)encodeParameters:(NSDictionary *)parameters {

NSMutableArray *list = [NSMutableArray new];

for (NSString *key in [parameters allKeys]) {
    id obj = [parameters objectForKey:key];
    NSString *path = [NSString stringWithFormat:@"%@=%@", key, obj];
    [list addObject:path];
}

return [[list componentsJoinedByString:@"&"] dataUsingEncoding:NSUTF8StringEncoding];

}

并使用它：

[request setValue:@"application/x-www-form-urlencoded" forHTTPHeaderField:@"Content-Type"];
[request setHTTPMethod:@"POST"];
[request setHTTPBody:[self encodeParameters:parameters]];

Answer 9

此版本处理参数编码并以'+'代替空格。

extension String {
    static let formUrlencodedAllowedCharacters =
        CharacterSet(charactersIn: "0123456789" +
            "abcdefghijklmnopqrstuvwxyz" +
            "ABCDEFGHIJKLMNOPQRSTUVWXYZ" +
            "-._* ")

    public func formUrlencoded() -> String {
        let encoded = addingPercentEncoding(withAllowedCharacters: String.formUrlencodedAllowedCharacters)
        return encoded?.replacingOccurrences(of: " ", with: "+") ?? ""
    }
}

class HTTPUtils {
    public class func formUrlencode(_ values: [String: String]) -> String {
        return values.map { key, value in
            return "\(key.formUrlencoded())=\(value.formUrlencoded())"
        }.joined(separator: "&")
    }
}

let headers = [
    "content-type": "application/x-www-form-urlencoded; charset=utf-8"
]

let body = HTTPUtils.formUrlencode([
    "field": "value"
])

var request = try URLRequest(url: url, method: .post, headers: headers)
request.httpBody = body.data(using: .utf8)

URLSession.shared.dataTask(with: request, completionHandler: { ... }).resume()

Answer 10

从 Swift 5 开始，以下代码已经过测试今天可以工作。

let url = URL(string: "https://something")
var request = URLRequest(url: url!)
request.setValue("application/x-www-form-urlencoded", forHTTPHeaderField: "Content-Type")
request.httpMethod = "POST"
let post = "parameter1=abc&parameter2=abc"
let postData = post.data(using: String.Encoding.ascii, allowLossyConversion: true)!
request.httpBody = postData

Answer 11

<!DOCTYPE html>
<html>
<head>
<link rel="stylesheet" href="https://openlayers.org/en/v4.0.1/css/ol.css" type="text/css">
<style>
.map {
        height: 400px;
        width: 100%;
      }
body {font-family: "Lato", sans-serif;}

/* Style the tab */
div.tab {
    overflow: hidden;
    border: 1px solid #ccc;
    background-color: #f1f1f1;
}

/* Style the buttons inside the tab */
div.tab button {
    background-color: inherit;
    float: left;
    border: none;
    outline: none;
    cursor: pointer;
    padding: 14px 16px;
    transition: 0.3s;
    font-size: 17px;
}

/* Change background color of buttons on hover */
div.tab button:hover {
    background-color: #ddd;
}

/* Create an active/current tablink class */
div.tab button.active {
    background-color: #ccc;
}

/* Style the tab content */
.tabcontent {
    display: none;
    padding: 6px 12px;
    border: 1px solid #ccc;
    border-top: none;
}

/* Style the close button */
.topright {
    float: right;
    cursor: pointer;
    font-size: 20px;
}

.topright:hover {color: red;}
</style>
</head>
<body>

<p>Click on the x button in the top right corner to close the current tab:</p>

<div class="tab">
  <button class="tablinks" onclick="openCity(event, 'London')" id="defaultOpen">London</button>
  <button class="tablinks" onclick="openCity(event, 'Paris')">Paris</button>
  <button class="tablinks" onclick="openCity(event, 'Tokyo')">Tokyo</button>
</div>

<div id="London" class="tabcontent">
  <span onclick="this.parentElement.style.display='none'" class="topright">x</span>
  <h3>London</h3>
  <p>London is the capital city of England.</p>
</div>

<div id="Paris" class="tabcontent">
  <span onclick="this.parentElement.style.display='none'" class="topright">x</span>
  <h3>Paris</h3>
  <p>Paris is the capital of France.</p>
  <div id="map" class="map"></div>
</div>

<div id="Tokyo" class="tabcontent">
  <span onclick="this.parentElement.style.display='none'" class="topright">x</span>
  <h3>Tokyo</h3>
  <p>Tokyo is the capital of Japan.</p>
</div>
<script src="https://openlayers.org/en/v4.0.1/build/ol.js" type="text/javascript"></script>
<script>
function openCity(evt, cityName) {
    var i, tabcontent, tablinks;
    tabcontent = document.getElementsByClassName("tabcontent");
    for (i = 0; i < tabcontent.length; i++) {
        tabcontent[i].style.display = "none";
    }
    tablinks = document.getElementsByClassName("tablinks");
    for (i = 0; i < tablinks.length; i++) {
        tablinks[i].className = tablinks[i].className.replace(" active", "");
    }
    document.getElementById(cityName).style.display = "block";
    evt.currentTarget.className += " active";
}

// Get the element with id="defaultOpen" and click on it
document.getElementById("defaultOpen").click();

    var map = new ol.Map({
        target: 'map',
        layers: [
          new ol.layer.Tile({
            source: new ol.source.OSM()
          })
        ],
        view: new ol.View({
          center: ol.proj.fromLonLat([37.41, 8.82]),
          zoom: 4
        })
      });
</script>

</body>
</html>

扩展词典

let params:[String: Any]
if "application/x-www-form-urlencoded" {
let bodyData = params.stringFromHttpParameters()
self.request.httpBody = bodyData.data(using: String.Encoding.utf8)}
if "application/json"{
  do {
    self.request.httpBody = try JSONSerialization.data(withJSONObject: params, options: JSONSerialization.WritingOptions())
  } catch {
    print("bad things happened")
  }
}

使用application / x-www-form-urlencoded的POST请求

11 个答案: