Question

我只想访问类

中声明的函数中的特定值

class Animal
{
    var $name;

    function __Construct($names){
        $this->name=$names;
    }
}

class Dog extends Animal 
{
    function prop($ht, $wt, $ja)
    {
        $height=$ht;
        $weight=$wt;
        $jaw=$ja;
    }
}

$dog= new dog('Pug');
$dog->prop(70, 50, 60);

我想仅回显dog函数prop中的特定值。

类似于dog->prop->jaw;

这是怎么做到的？

Answer 1

听起来你想要这样的东西......

class Dog extends Animal {
    private $props = array();

    public function prop($height, $width, $jaw) {
        $this->props = array(
            'height' => $height,
            'width'  => $width,
            'jaw'    => $jaw
        );
        return $this; // for a fluent interface
    }

    public function __get($name) {
        if (array_key_exists($name, $this->props)) {
            return $this->props[$name];
        }
        return null; // or throw an exception, whatever
    }
}

然后你可以执行

echo $dog->prop(70, 50, 60)->jaw;

或单独

$dog->prop(70, 50, 60);
echo $dog->jaw;

从类中的函数中获取变量的特定值

1 个答案: