Question

表格：

<form  id="regd" enctype="multipart/form-data"  method="post" action="register_action.php">
    <tr>
    <td>Name</td>
    <td><input type="text" size="26" name="txtname" required="required" />     </td></tr>
        <tr>
    <td>Em@il id</td>
    <td><input type="email" size="26" name="txtemail" required="required" /> </td></tr>
    <tr>
    <td>Password</td>
    <td><input type="password" size="26" name="pwd1" required="required"> </td></tr>


            <tr> <td>Country</td>
    <td><div><select  required="true" name="country" id="country">
<option value="">Select Country</option>

<?php while ($row=mysql_fetch_array($result)) { ?>

<option value=<?php echo $row['country_id']?>"<?php echo  $row['country_name']?>"><?php echo $row['country_name']?></option>
<?php } ?>
</select></div> </td></tr>
<tr>
    <td>State/td>
    <td>
    <div id="statediv">
    <input name="state"  type="text" maxlength="255" value="" required="required" title="Select Country first"/> 
</div> 
</td></tr>
 <tr>
 <td><input id="btn_cancel" type="reset" value="Cancel" class="regdbutton"></td>
 <td><input id="btn_submit" type="submit" /></td></tr>
</form>

这是表单，我想在其中输入值到数据库，并且它也是在没有那个状态的情况下进入，它已经通过Ajax加载了。下面是代码（我已经跳过了那个函数XmlHTTP的东西）因为这会使代码更长）

Ajax Part：

<script language="javascript" type="text/javascript">
function getState(countryid) {      
var strURL="findState.php?country="+countryid;
var req = getXMLHTTP(); 
if (req) {  
req.onreadystatechange = function() {
if (req.readyState == 4) {
if (req.status == 200)     {                        
                         document.getElementById('statediv').innerHTML=req.responseText;
                    document.getElementById('citydiv').innerHTML='<select name="city">'+
                    '<option>Select City</option>'+
                    '</select>';                        
} else {
alert("Problem while using XMLHTTP:\n" + req.statusText);
}
}               
}           
req.open("GET", strURL, true);
req.send(null);
}       
}
</script>

寻找城市：

<?php $country=intval($_GET['country']);
include("config.php");
$query="SELECT state_id,state_name FROM state WHERE country_id='$country'";
$result=mysql_query($query);
?>
<select style="width:190px;" class="element select medium" name="state" onchange="getCity(<?php echo $country?>,this.value)" title="State">
<option>Select State</option>
<?php while ($row=mysql_fetch_array($result)) { ?>
<option value=<?php echo $row['state_id']?>"<?php echo $row['state_name']?>"><?php echo $row['state_name']?></option>
<?php } ?>
</select>

我没有发布我的操作代码，因为它运行正常，错误“未定义的索引状态”并且值没有输入。

输入动态加载（在ajax中）数据到数据库中

0 个答案: