Question

我想在ObservableCollection中随机播放内容，

public static ObservableCollection<whatsnewCompleteData> whatsnewCompleteList = new ObservableCollection<whatsnewCompleteData>();

 for (int i = 0; i < whatsnewfeed.feed.entry.Count; i++)
 {              
    whatsnewCompleteList.Add(new whatsnewCompleteData(i, content[i]);
 }

如果是正常列表，我可以轻松进行随机播放！但是observablecollection直接绑定到UI。我唯一能做的就是每次初始化时都使用一个随机数。所以这里的范围是

0 < whatsnewfeed.feed.entry.Count

如何生成随机数并涵盖从0到whatsnewfeed.feed.entry.count的所有值？

Answer 1

首先，您可以按照您的建议对就地ObservableCollection的数据进行随机播放，或者您可以创建一个新数据，然后覆盖{{1} }。

考虑这个案例：

ObservableCollection

在你的方法中：

public static ObservableCollection<whatsnewCompleteData> whatsnewCompleteList = new ObservableCollection<whatsnewCompleteData>();

// A bindable property
public ObservableCollection<whatsnewCompleteData> WhatsNewCompleteList
{
    get
    {
        return whatsnewCompleteList;
    }
    set
    {
        whatsnewCompleteList = value;
        // Your property changed notifier method
        OnPropertyChanged("WhatsNewCompleteList");
    }
}

这将覆盖当前列表并更新您的绑定，而不必担心用户界面会被吓坏。

另一种选择是简单地创建一个新的值列表，然后在// content should obviously be whatever object type you need to get // (or already have) public void Shuffle(List<object> content) { // Note: you don't have to initialize an observable collection like this. // You can also create a list, shuffle it as you would normally, then call // new ObservableCollection<whatsnewCompleteData(shuffledList); var newWhatsnewCompleteList = new ObservableCollection<whatsnewCompleteData>(); for (int i = 0; i < whatsnewfeed.feed.entry.Count; i++) { newWhatsnewCompleteList.Add(new whatsnewCompleteData(i, content[i]); } WhatsNewCompleteList = newWhatsnewCompleteList; }集合上调用Clear()并使用新值填充它。

希望这有助于编码！

在初始化Observable Collection时进行洗牌

1 个答案: