我以 MS Access 2000文件格式
以下表的形式从第三方获取数据以下是这些表格的样本数据。
Papers表和示例数据
+----+----------+
| ID | PaperID |
+----+----------+
| 1 | 658 |
| 2 | 659 |
| 3 | 660 |
| 4 | 661 |
| 5 | 662 |
| 6 | 663 |
| 7 | 664 |
+----+----------+
PaperTags表和示例数据
+----+----------+----------------------------------------+
| ID | PaperID | TagID |
+----+----------+----------------------------------------+
| 1 | 663 | 3 |
| 2 | 663 | 15 --Y |
| 3 | 663 | 17 |
| 4 | 663 | 18 --Y |
| 5 | 664 | 14 |
| 62 | 658 | 9 |
| 63 | 658 | 14 |
| 64 | 658 | 17 |
| 65 | 659 | 15 --Y |
| 66 | 659 | 17 |
| 67 | 659 | 18 --Y |
| 68 | 660 | 17 |
| 69 | 660 | 18 --N as it has only 18 and not 15 |
| 70 | 661 | 10 |
| 71 | 661 | 17 |
| 72 | 661 | 18 --N as it has only 18 and not 15 |
| 73 | 662 | 18 --N as it has only 18 and not 15 |
| 74 | 662 | 14 |
| 75 | 662 | 17 |
| 76 | 662 | 18 --N as it has only 18 and not 15 |
+----+----------+----------------------------------------+
现在，我的最终用户将传递一个或多个TagID，例如15和18，我的目标是查找所有具有所有这些TagID的PaperID。在这些例子中，我需要返回663和659
我已经尝试过以下查询，但如果数据中有任何故障，那么它就不起作用了。例如，PaperID 662在表中出现两次，具有相同的TagID，因此count（PaperID）= 2结果为真，它将以我的结果结束。
select Count(PaperID), PaperID from PaperTags
group by TagID, PaperID
having TagID = 15 or TagID = 18
and count(PaperID) = 2
我尝试的另一个查询是
select * from Papers
where Papers.PaperID
in
(
select PaperTags.PaperID from PaperTags
where (PaperTags.Tagid = 15 or PaperTags.Tagid = 18)
and PaperTags.PaperID = Papers.PaperID
)
我已经通过了下面的文章但是当我使用MSAccess时，我不能使用这种方法。
Select records from a table where all other records with same foreign key have a certain value
我认为必须有更好的过滤方法。非常感谢任何帮助。
答案 0 :(得分：0)
这样的事情：
SELECT G.ContentID
FROM (
SELECT PT.ContentID, PT.TagID
FROM PaperTags AS PT
WHERE PT.TagID IN (15, 18)
GROUP BY PT.ContentID, PT.TagID
) AS G
GROUP BY G.ContentId
HAVING Count(*) = 2