使用JOIN更新选择

Question

我的困境是我需要在我的事务表中将subscription_id更新为基于相同billingid的新subscription_id。

我的订阅表包含来自不同账单的多个订阅记录的成员。我很难将这个更新选择/连接放在mysql上。

TBL subscription_id

+--------------------+---------------+----------+
| subscription_id    | memberid      | billerid |
+--------------------+---------------+----------+
12345                | A             | ?        |
+--------------------+---------------+----------+
67890                | A             | 13       |
+--------------------+---------------+----------+
11222                | B             | 13       |
+--------------------+---------------+----------+
91422                | B             | ?        |
+--------------------+---------------+----------+

TBL交易

+---------------+-----------------+----------+
| trans_id      | subscription_id | billerid |
+---------------+-----------------+----------+
00012           | 12345           | 13       |
+---------------+-----------------+----------+
02013           | 12345           | 13       |
+---------------+-----------------+----------+
08013           | 11222           | 13       |
+---------------+-----------------+----------+
50013           | 11222           | 13       |
+---------------+-----------------+----------+

Answer 1

UPDATE transaction AS t
JOIN (SELECT s1.subscription_id AS old_subid, 
             s2.subscription_id AS new_subid,
             s2.billerid AS billerid
      FROM subscription_id AS s1
      JOIN subscription_id AS s2 ON s1.memberid = s2.memberid
      WHERE s1.billerid = '?'
        AND s2.billerID != '?') AS s
ON t.billerid = s.billerid AND t.subscription_id = s.old_subid
SET t.subscription_id = s.new_subid

DEMO

我想我想出了一个更适合你最新评论的简单版本：

UPDATE transaction AS t
JOIN subscription_id AS s1 
    ON s1.subscription_id = t.subscription_id 
        AND s1.billerid != t.billerid
JOIN subscription_id AS s2 
    ON s1.memberid = s2.memberid 
        AND s2.subscription_id != s1.subscription_id 
        AND s2.billerid = t.billerid
SET t.subscription_id = s2.subscription_id

DEMO