Question

在我添加案例陈述之前，我没有收到错误。如果H1或H2手机字段为空或无效，我需要添加案例陈述以提供家庭电话号码作为备份（最好的方式我知道如何做，作为新手）。出于某种原因，我在查询表达式中收到语法错误（缺少运算符）。它注意到两个案例陈述的错误。据我所知，他们写得正确......谁知道怎么了？感谢。

SELECT [H1 Last Name] & ", " & [H1 First Name] as [Full Name],[H1 E-Mail]
CASE
     WHEN [H1 Cell Phone] IS NULL
     THEN [Home Phone]
     ELSE [H1 Cell Phone] END as [Phone]

FROM NameLookup 
WHERE (((NameLookup.[H1 Last Name]) NOT LIKE '%SPEC%') OR ((NameLookup.[H1 Last Name]) NOT LIKE '%MODEL%')) AND ((NameLookup.[H1 Last Name]) IS NOT NULL)

UNION

SELECT [H2 Last Name] & ", " & [H2 First Name] as [Full Name],[H2 E-Mail]
CASE
     WHEN [H2 Cell Phone] IS NULL
     THEN [Home Phone]
     ELSE [H2 Cell Phone] END as [Phone]

FROM NameLookup 
WHERE (((NameLookup.[H1 Last Name]) NOT LIKE '%SPEC%') OR ((NameLookup.[H1 Last Name]) NOT LIKE '%MODEL%')) AND ((NameLookup.[H1 Last Name]) IS NOT NULL)


Order By 1;

Answer 1

您是否在MS Access ACE中使用它？案例不可用，请使用IIF(argument, true value, false value)

SELECT [H1 Last Name] & ", " & [H1 First Name] as [Full Name],[H1 E-Mail],
IIF ( [H1 Cell Phone] IS NULL, [Home Phone], [H1 Cell Phone] ) AS Phone
FROM NameLookup

访问SQL函数：http://www.techonthenet.com/access/functions/

Access 2013：为什么我会收到此语法错误？

1 个答案: