Question

以下是在“少于14天”或“少于30天”部分标记order_date的查询。有一个订单日期是未来的日期，它也包含在“不到14天”内。

我尝试了以下内容：

WHEN DATEDIFF(DD,OH.order_date, GETDATE()) < 14 AND DATEDIFF(DD,OH.order_date, GETDATE()) < GETDATE() THEN 'Less than 14 days'

未来的日期仍然存在。请指教

原始代码：

SELECT CS.cust_id, OH.order_date,
    CASE
    WHEN DATEDIFF(DD,OH.order_date, GETDATE()) < 14 THEN 'Less than 14 days'
    WHEN DATEDIFF(DD,OH.order_date, GETDATE()) < 30 THEN 'Less than 30 days'
    END
 AS 'orderAge'
FROM customers AS CS
INNER JOIN order_headers AS OH ON OH.cust_id = CS.cust_id
ORDER BY cust_id, order_date;

Answer 1

    SELECT CS.cust_id, OH.order_date,
        CASE
        WHEN DATEDIFF(DD,OH.order_date, GETDATE()) < 0 THEN 'Future date'
        WHEN DATEDIFF(DD,OH.order_date, GETDATE()) < 14 THEN 'Less than 14 days'
        WHEN DATEDIFF(DD,OH.order_date, GETDATE()) < 30 THEN 'Less than 30 days'
        END
     AS 'orderAge'
    FROM customers AS CS
    INNER JOIN order_headers AS OH ON OH.cust_id = CS.cust_id
    ORDER BY cust_id, order_date;

Answer 2

尝试使用代码，但使用0作为边界点。您只需要DATEDIFF函数的正返回值。

WHEN DATEDIFF(DD,OH.order_date, GETDATE()) < 14 AND DATEDIFF(DD,OH.order_date, GETDATE()) > 0 THEN 'Less than 14 days'

没有未来日期SQL查询

2 个答案: