为什么我的UILabel没有定型?

时间:2014-03-09 23:19:01

标签: ios cocoa-touch uilabel

我几个小时以来一直困在一个问题上,似乎无法解决这个问题。我是Objective-C的新手,我真的很烦我不能得到这个。我想在NSLog中显示bmiLabel值,但我的bmiLabel始终显示NULL

这是我的代码: ViewController.h:

#import <UIKit/UIKit.h>

@interface ViewController : UIViewController<UITextFieldDelegate>
@property (strong, nonatomic) IBOutlet UITextField *num1;
@property (strong, nonatomic) IBOutlet UITextField *num2;
@property (strong, nonatomic) IBOutlet UILabel *resultLabel;
@property (strong, nonatomic) IBOutlet UILabel *bmiLabel;
- (IBAction)bmiButton:(id)sender;
@end

ViewController.m:

#import "ViewController.h"

@interface ViewController ()

@end

@implementation ViewController

@synthesize num1, num2, resultLabel, bmiLabel;

- (void)viewDidLoad
{
[super viewDidLoad];
// Do any additional setup after loading the view, typically from a nib.
}

- (void)didReceiveMemoryWarning
{
[super didReceiveMemoryWarning];
// Dispose of any resources that can be recreated.
}

-(BOOL) textFieldShouldReturn:(UITextField *)textField
{
[textField resignFirstResponder];
return YES;
}

- (IBAction)bmiButton:(id)sender
{
float sum = [self.num2.text floatValue] / ([self.num1.text floatValue] *
[self.num1.text floatValue]);
NSString *Output = nil;
Output = [[NSString alloc] initWithFormat:@"%.2f", sum];
self.resultLabel.text = Output;

NSString *mystring;
NSString * bmi = [[NSString alloc] NSStringWithFormat:@"%@", mystring];
self.bmiLabel.text = bmi;

if(sum <= 18.5)
{
    NSLog(@"You are underweight", mystring);

}
if(sum <= 18.5)
{
    NSLog(@"you are normal");
}

if (sum <= 25.0)
{
    NSLog(@"You are overweight");
}

if(sum <= 30)
{
NSLog(@"You are obese");
}

}
@end

5 个答案:

答案 0 :(得分:1)

嗯,试着成为一个小小的通灵者,我注意到你实际上没有在BMI案件中加入任何东西。试试这个:

- (IBAction)bmiButton:(id)sender {
    float sum = [self.num2.text floatValue] / ([self.num1.text floatValue] *
                         [self.num1.text floatValue]);

    NSString *Output = [NSString stringWithFormat:@"%.2f", sum];
    self.resultLabel.text = Output;

    NSString *mystring= nil;

    if (sum <= 18.5) {
        mystring = @"You are underweight";
    } else if (sum <= 25.0) {
        mystring = @"you are normal";
    } else if (sum <= 30.0){
        mystring = @"You are overweight";
    } else {
        mystring = @"You are obese:";
    }
    self.bmiLabel.text = mystring;

}

答案 1 :(得分:0)

我不知道你在问什么,但这里有一个错误:

NSString *mystring;
NSString * bmi = [[NSString alloc] NSStringWithFormat:@"%@", mystring];
self.bmiLabel.text = bmi;

首先,你的字符串格式设置器:

[[NSString alloc] NSStringWithFormat:@"someformat: %@", someVariable];

应该是:

[NSString stringWithFormat:@"someformat: %@", someVariable];

但是,如果这些是正确的,这仍然会有这个问题:

NSString * bmi = [NSString stringWithFormat:@"%@", mystring];

当mystring已经是一个字符串时,这很奇怪。它适用于:

NSString * bmi = mystring;

基本上,这三行是等同于:

NSString * mystring;
self.bmiLabel.text = mystring;

回答

问题是,你从来没有为mystring分配值

答案 2 :(得分:0)

我认为[[NSString alloc] NSStringWithFormat:@"%@", mystring];代码存在问题。请尝试下面的代码

 NSString *mystring;
 NSString * bmi = [NSString stringWithFormat:@"%@", mystring];
 self.bmiLabel.text = bmi;

此外,您必须初始化mystring。如果你不mystring总是返回null。

答案 3 :(得分:0)

此代码无用,因为bmi将是一个空字符串。所以bmiLabel将是空的。

NSString *mystring;
NSString * bmi = [[NSString alloc] NSStringWithFormat:@"%@", mystring];
self.bmiLabel.text = bmi;  

你的其余代码很好。虽然在我看来你在代码中使用了太多的对象。例如,您的NSString不是必需的,您可以写这个

float sum = [self.num2.text floatValue] / ([self.num1.text floatValue] *
[self.num1.text floatValue]);
self.resultLabel.text = [[NSString alloc] initWithFormat:@"%.2f", sum];

答案 4 :(得分:0)

此:

[[NSString alloc] NSStringWithFormat:@“%@”,mystring];

StringWithFormat是一个将发送给类的类方法:

string = [NSString stringWithFormat:@"some string"];

这告诉类给你一个已经分配和初始化的字符串。

在你的情况下你应该(可以)使用:

string = [[NSString alloc]initWithFormat:@"some string"];

另外,关于代码中的这一行:

NSString * bmi = [[NSString alloc] NSStringWithFormat:@"%@", mystring];

你可以这样做:

[[self bmiLabel]setText:[[NSString alloc]initWithString:mystring]];

或者如果您更喜欢点符号

self.bmiLabel.text = [[NSString alloc]initWithString:mystring]];
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