Question

如何在postgres中隐藏oracle的connect_by_root查询。例如：这是一个oracle查询。

select fg_id, connect_by_root fg_id as fg_classifier_id
from fg
start with parent_fg_id is null
connect by prior fg_id = parent_fg_id

Answer 1

您将使用一个递归公用表表达式，它只是通过递归级别“携带”根目录：

with recursive fg_tree as (
  select fg_id, 
         fg_id as fg_clasifier_id -- <<< this is the "root" 
  from fg
  where parent_fg_id is null -- <<< this is the "start with" part
  union all
  select c.fg_id, 
         p.fg_clasifier_id
  from fg c 
    join fg_tree p on p.fg_id = c.parent_fg_id -- <<< this is the "connect by" part
) 
select *
from fg_tree;

手册中有关递归公用表表达式的更多详细信息：http://www.postgresql.org/docs/current/static/queries-with.html

postgres中的connect_by_root等价物

1 个答案: