Question

我想听听我网站上发生的所有事件。我使用monitorEvents()命令，但此命令仅将事件打印到控制台，我想设置一个回调函数，以便对该数据进行一些操作而不将其打印到控制台。

有没有聪明的方法可以做到这一点？

Answer 1

您可以尝试这样的事情：

var eventsList = ["mousedown", "mouseup", "click", "dblclick", "mousemove",
    "mouseover", "mouseout", "mousewheel", "keydown", "keyup", "keypress", 
    "textInput", "touchstart", "touchmove", "touchend", "touchcancel", "resize",
    "scroll", "zoom", "focus", "blur", "select", "change", "submit", "reset"];

var callbackFunction = function(element, eventName) {
  console.log('Triggered event ' + eventName);
};

var elements = document.querySelectorAll('*');
for (var i = 0; i < elements.length; i++) {
  for (var j = 0; j < eventsList.length; j++) {
    var element = elements[i];
    var event = eventsList[j];

    element.addEventListener(event,
        callbackFunction.bind(this, element, event), true);
  }
}

Answer 2

我找到了最好的方法。此代码基于原始monitorEvents()命令。使用此脚本，可以收听所有Chrome事件并使用自定义功能处理它们......您只需编辑“eventHandler”功能即可。要试一试，只需复制到Chrome控制台，然后使用：startMonitorEvents（window，eventHandler）;

/**
* @param {Event} event
*/
function eventHandler(event)
{
    // Do whatever you want here... 

    console.log("my custom handler… ", event.type, event);
}

/**
* @param {Object} object
* @param {Function} callback
*/
function startMonitorEvents(object, callback)
{
    if (!object || !object.addEventListener || !object.removeEventListener)
                    return;
    var types = getEventsForMonitor();
    for (var i = 0; i < types.length; ++i) {
                    object.removeEventListener(types[i], callback, false);
                    object.addEventListener(types[i], callback, false);
    }
}

function getEventsForMonitor()
{
    var result = [];

    // mouse
    result.splice(0, 0, "mousedown", "mouseup", "click", "dblclick", "mousemove", "mouseover", "mouseout", "mousewheel");
    // key
    result.splice(0, 0, "keydown", "keyup", "keypress", "textInput");
    // touch
    result.splice(0, 0, "touchstart", "touchmove", "touchend", "touchcancel");
    // control
    result.splice(0, 0, "resize", "scroll", "zoom", "focus", "blur", "select", "change", "submit", "reset");
    // others
    result.splice(0, 0, "load", "unload", "abort", "error", "select", "change", "submit", "reset", "focus", "blur", "resize", "scroll", "search", "devicemotion", "deviceorientation");

    return result;
}

// Usage: startMonitorEvents(window, eventHandler);

Answer 3

Firebug内部使用Paul Rad的解决方案，其中包含以下事件列表：

["DOMActivate", "DOMAttrModified", "DOMCharacterDataModified", "DOMFocusIn", "DOMFocusOut", "DOMNodeInserted", "DOMNodeInsertedIntoDocument", "DOMNodeRemoved", "DOMNodeRemovedFromDocument", "DOMSubtreeModified", "abort", "beforeunload", "blur", "change", "click", "composition", "compositionend", "compositionstart", "contextmenu", "copy", "cut", "dblclick", "dragdrop", "dragenter", "dragexit", "draggesture", "dragover", "error", "focus", "input", "keydown", "keypress", "keyup", "load", "mousedown", "mousemove", "mouseout", "mouseover", "mouseup", "overflow", "overflowchanged", "paint", "paste", "reset", "resize", "scroll", "select", "submit", "text", "touchcancel", "touchend", "touchenter", "touchleave", "touchmove", "touchstart", "underflow", "unload"]

收听Chrome浏览器中的所有活动

3 个答案: