我有一个我不明白的错误。你能帮助我吗?

时间:2014-03-13 16:46:00

标签: mysql sql phpmyadmin

我在“reportsTo”中的内容与employeeNumber类似,那么问题是什么?

SELECT firstName,lastName,temp.count
FROM employees
where employeeNumber  in(

SELECT reportsTo, COUNT( * ) AS count
FROM employees
GROUP BY reportsTo
) as temp

2 个答案:

答案 0 :(得分:2)

用于IN子句的子查询无法返回多个列,因此您无法在其中包含SELECT reportsTo, COUNT( * ) AS count。您可能希望加入子查询,如下所示:

SELECT firstName,lastName,temp.count
FROM employees
INNER JOIN (
    SELECT reportsTo, COUNT( * ) AS count
    FROM employees
    GROUP BY reportsTo
) temp ON employees.employeeNumber = temp.reportsTo

免责声明:我不使用MySQL,因此上述语法可能不准确。

您可能也会在尝试使用count作为列名时遇到问题。重命名或转义它(SQL Server使用[],不确定MySQL。)

答案 1 :(得分:0)

不知道你想要什么,只需将其改为:

SELECT firstName,
       lastName
  FROM employees 
 WHERE employeeNumber  in( SELECT reportsTo 
                             FROM employees 
                         GROUP BY reportsTo )

删除计数和别名会有效,但我觉得你真正想要的是:

SELECT manager.firstName,
       manager.lastName,
       temp.count        AS number_of_directs
  FROM (SELECT reportsTo, 
               COUNT( * ) AS count
          FROM employees
      GROUP BY reportsTo) as temp
INNER JOIN employees AS manager ON manager.reportsTo = temp.reportsTo
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