Question

我使用OpenFileDialog()上传文件，因此我可以阅读.csv文件并将其添加到数据网格中。但是，如果在未选择文件的情况下关闭OpenFileDialog，则会崩溃。所以我将它放在try { } catch { }块中作为临时修复。

有人可以为未被选中的文件提供更好的解决方案吗？

修改这是我的OpenFileDialog代码：

// ... Code to Setup OFD here ...

// If the search for the file is OK (i.e. the file exists), stores the filename in a string.
if (openFileDialog1.ShowDialog() == DialogResult.OK)
{
    fileName = openFileDialog1.FileName;
    Console.WriteLine(fileName);
}
// Runs the Populate Data Grid View method.
UploadFromExternalSource();

这是AddtoDataGrid代码：

// Try/catch used if a file was not uploaded.
try
{
    // Reads the text and splits the text into rows by each new line.
    importFile = File.ReadAllText(CView.fileName).Split('\n');
    foreach (string line in importFile)
    {
        // Splits each line into indiviual columns each time it comes in contact with a comma (",")
        // then increments the line count (determined by the new line) by 1.
        data = line.Split(',');
        CView.dataGridView1.Rows.Add(data);
        lineCount++;
    }
}
catch (Exception e) { Console.WriteLine(e.Message); }

Answer 1

OpenFileDialog.ShowDialog()将返回DialogResult。如果用户选择了文件，您可以检查DialogResult.OK。

示例：

var opf = new OpenFileDialog();

if(opf.ShowDialog() == DialogResult.OK)
{
//do something
}

替换try {} catch {}块以进行文件上载

1 个答案: