Question

这个SQL查询的正确Django视图和HTML是什么？：

SELECT 
  hood.`hood`,
  COUNT(business.`id`) AS TOTAL 
FROM
 `hood` 
JOIN business 
  ON hood.`id` = business.`hood_id` 
WHERE business.`city_id` = 8 
GROUP BY hood.`id` 
ORDER BY TOTAL DESC 
LIMIT 5 ;

我的模特是：

class Hood(models.Model):
    name = models.CharField(max_length=50, db_column='hood')
    slugname = models.SlugField(max_length=50, blank=True)
    city = models.ForeignKey('City', related_name='hoods')
    location = models.ForeignKey('Location', related_name='hoods')
    switch = models.SmallIntegerField(null=True, blank=True, default='1')
    class Meta:
        db_table = 'hood'  


class Business(models.Model):
    name = models.CharField(max_length=50, db_column='name', blank=True)
    slugname = models.SlugField(max_length=50, blank=True)
    city = models.ForeignKey('City', related_name="business")
    hood = models.ForeignKey('Hood', null=True, blank=True, related_name="business")
    ....

HTML模板？

谢谢！

Answer 1

查看有关聚合的文档： https://docs.djangoproject.com/en/1.6/topics/db/aggregation/

您应该能够编写一个返回查询集的视图，其计数类似于：

from django.db.models import Count
Hood.objects.filter(business__city_id=8).annotate(bus_count=Count('business__id'))

至于HTML，这完全取决于你。但是，如果您提供该查询集，则可以使用{{ object.bus_count }}获取计数。

使用JOIN和GROUP BY SQL查询的Django COUNT

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