仅打印＆＃39; +＆＃39;或者＆＃39; - ＆＃39;如果字符串匹配（有两个条件）

Question

我想为我的实际代码添加两个附加条件：print＆＃39; +＆＃39;如果在File2字段5中大于35且字段7大于90。

代码：

while read -r line
do
    grep -q "$line" File2.txt && echo "$line +" || echo "$line -"
done < File1.txt '

输入文件1：

HAPS_0001
HAPS_0002
HAPS_0005
HAPS_0006
HAPS_0007
HAPS_0008
HAPS_0009
HAPS_0010

输入文件2（制表符分隔）：

Query   DEG_ID  E-value Score   %Identity   %Positive   %Matching_Len
HAPS_0001   protein:plasmid:149679  3.00E-67    645 45  59  91
HAPS_0002   protein:plasmid:139928  4.00E-99    924 34  50  85
HAPS_0005   protein:plasmid:134646  3.00E-98    915 38  55  91
HAPS_0006   protein:plasmid:111988  1.00E-32    345 33  54  86
HAPS_0007   -   -   0   0   0   0
HAPS_0008   -   -   0   0   0   0
HAPS_0009   -   -   0   0   0   0
HAPS_0010   -   -   0   0   0   0

所需的输出（制表符分隔）：

HAPS_0001   +
HAPS_0002   -
HAPS_0005   +
HAPS_0006   -
HAPS_0007   -
HAPS_0008   -
HAPS_0009   -
HAPS_0010   -

谢谢！

Answer 1

这应该有效：

$ awk '
BEGIN {FS = OFS = "\t"} 
NR==FNR {if($5>35 && $7>90) a[$1]++; next}
{print (($1 in a) ? $0 FS "+" : $0 FS "-")}' f2 f1
HAPS_0001       +
HAPS_0002       -
HAPS_0005       +
HAPS_0006       -
HAPS_0007       -
HAPS_0008       -
HAPS_0009       -
HAPS_0010       -

Answer 2

join file1.txt <( tail -n +2 file2.txt) | awk '
 $2 = ($5 > 35 && $7 > 90)?"+":"-" { print $1, $2 }'

您不关心输出中的第二个字段，因此请使用适当的输出符号覆盖它。