如何使用XmlAttributeOverrides覆盖集合元素的xml元素名称?

时间:2010-02-11 19:23:24

标签: c# xml-serialization override

我有一个非常基本的对象对象模型,由System.Xml.XmlSerialization东西序列化。我需要使用XmlAttributeOverrides功能为子元素集合设置xml元素名称。

public class Foo{
  public List Bars {get; set; }
}

public class Bar {
  public string Widget {get; set; }
}

使用标准的xml序列化程序,这将显示为

 <Foo>
  <Bars>
    <Bar>...</Bar>
  </Bars>
 </Foo>

我需要使用XmlOverrideAttributes来说明

 <Foo>
  <Bars>
    <SomethingElse>...</SomethingElse>
  </Bars>
 </Foo>

但我似乎无法让它重命名集合中的子元素...我可以重命名集合本身...我可以重命名根...不确定我做错了什么。< / p>

这是我现在的代码:

XmlAttributeOverrides xOver = new XmlAttributeOverrides();

var bars = new XmlElementAttribute("SomethingElse", typeof(Bar));
var elementNames = new XmlAttributes();
elementNames.XmlElements.Add(bars);
xOver.Add(typeof(List), "Bars", elementNames);

StringBuilder stringBuilder = new StringBuilder();
StringWriter writer = new StringWriter(stringBuilder);
XmlSerializer serializer = new XmlSerializer(typeof(Foo), xOver);
serializer.Serialize(writer, someFooInstance);

string xml = stringBuilder.ToString();

但这根本不会改变元素的名称......我做错了什么?

感谢

2 个答案:

答案 0 :(得分:8)

为此,您需要[XmlArray][XmlArrayItem](理想情况下两者都要明确):

using System.Collections.Generic;
using System.IO;
using System.Xml.Serialization;
public class Foo {
    public List<Bar> Bars { get; set; }
}  
public class Bar {
    public string Widget { get; set; }
}
static class Program {
    static void Main() {
        XmlAttributeOverrides xOver = new XmlAttributeOverrides();
        xOver.Add(typeof(Foo), "Bars", new XmlAttributes {
            XmlArray = new XmlArrayAttribute("Bars"),
            XmlArrayItems = {
                new XmlArrayItemAttribute("SomethingElse", typeof(Bar))
            }
        });
        XmlSerializer serializer = new XmlSerializer(typeof(Foo), xOver);
        using (var writer = new StringWriter()) {
            Foo foo = new Foo { Bars = new List<Bar> {
                new Bar { Widget = "widget"}
            }};
            serializer.Serialize(writer, foo);
            string xml = writer.ToString();
        }            
    }
}

答案 1 :(得分:1)

德里克,

这对我有用 - 不确定它是否适合你:

public class Foo
{
    [XmlArrayItem(ElementName = "SomethingElse")]
    public List<Bar> Bars { get; set; }
}
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