Question

这句话有什么不对，因为它没有打印结果并显示空白页面我问了同样的问题，但几小时前差点不大但没有得到正确的解决方案

这是代码

    if(isset($_GET['ID'])){

    $page_id = $_GET['ID'];

    $select_query = $con->prepare("select ID, Title, image, Cost, Vid, content from mobs where ID=?"); 

    $select_query->execute()
    $select_query->bind_result($post_id, $post_title, $post_image, $post_cost, $post_vid, $post_content);

while ($select_query->fetch())
echo $post_id ,"<br>",
     $post_title;
 {

Answer 1

您忘记将$_GET["ID"]与您的查询进行参数化：

if($stmt = $con->prepare("SELECT ID, Title, image, Cost, Vid, content FROM mobs WHERE ID=?")){

  $stmt->bind_param("i", $_GET["ID"]); /* This is the part you're missing from your original post */
  $stmt->execute();
  $stmt->bind_result($post_id, $post_title, $post_image, $post_cost, $post_vid, $post_content);

  while($stmt->fetch()){ /* And I fixed your fetching of arrays */
    printf("%s<br>", $post_title); /* JUST SET WHAT YOU WANT TO OUTPUT HERE */
  } /* END OF WHILE LOOP */

} /* END OF PREPARED STATEMENT */

bind_result未获取结果

1 个答案: