当我尝试这个时,
Decimal m = Decimal.Parse(columns[1], System.Globalization.NumberStyles.AllowHexSpecifier);
我收到一个ArgumentException,说明了这个,
浮点数不支持数字样式AllowHexSpecifier 数据类型。
和列[1] = 4B414D000000011613C3 btw。
我做错了什么以及如何解决?
答案 0 :(得分:4)
Decimal
是浮点类型。请尝试使用int.Parse
。
答案 1 :(得分:3)
Decimal
是浮点类型,例如Single
,Double
,因此您无法通过标准方式解析
4B414.D000000011613C3eAF // <- '.' decimal point; 'e' exponent sign
另一方面,Decimal
接近int128
而我们没有超长整数。如果您的值不那么大(小于 2 ^ 63 ,大约 9.2e18 ),您可以尝试一下
// It's OK in your case:
// 4B414D000000011613C3 (hex) = 5422700088726126870 (dec) < 9223372036854775808
// use long.Parse() or ulong.Parse(): int is too small
Decimal result = long.Parse(columns[1], System.Globalization.NumberStyles.HexNumber);
如果超过 UInt64,您可以拆分您的值:
// to simplify the idea, I remove negative values support
String source = "4B414D000000011613C3";
String highPart = source.Remove(source.Length - 16);
String lowPart = source.Substring(source.Length - 16);
Decimal result =
ulong.Parse(highPart, System.Globalization.NumberStyles.HexNumber);
result = result * ulong.MaxValue + ulong.Parse(lowPart, System.Globalization.NumberStyles.HexNumber);
答案 2 :(得分:2)
您有一个20个字符的字符串,表示十六进制整数,并且您希望将其转换为数字格式。 20个字符是80位,因此它不适合整数,但它将适合十进制。十进制是128位浮点表示,具有96位尾数。没有可以执行此操作的内置转换功能。
我能想到的最佳策略就是这个。
有关详细信息,请参阅http://msdn.microsoft.com/en-us/library/bb1c1a6x%28v=vs.110%29.aspx。
答案 3 :(得分:0)
这基于msdn示例,其中十六进制值将转换为双精度。并采用相同的值来验证结果。
`double dnumber = 0;
long number;
bool result = Int64.TryParse(hexString,
NumberStyles.HexNumber, CultureInfo.InvariantCulture,
out number);
dnumber=BitConverter.Int64BitsToDouble(number);
return dnumber;`
要使用此程序,我给出了示例工作程序,请在控制台应用程序中使用它并检查结果。
`static void Main(string [] args) { const string formatter =“ {0,27:E16}”;
Console.WriteLine(string.Format(formatter, HexStringToDouble("0")));
Console.WriteLine(string.Format(formatter, HexStringToDouble("3FF0000000000000")));
Console.WriteLine(string.Format(formatter, HexStringToDouble("402E000000000000")));
Console.WriteLine(string.Format(formatter, HexStringToDouble("406FE00000000000")));
Console.WriteLine(string.Format(formatter, HexStringToDouble("41EFFFFFFFE00000")));
Console.WriteLine(string.Format(formatter, HexStringToDouble("3F70000000000000")));
Console.WriteLine(string.Format(formatter, HexStringToDouble("3DF0000000000000")));
Console.WriteLine(string.Format(formatter, HexStringToDouble("0000000000000001")));
Console.WriteLine(string.Format(formatter, HexStringToDouble("000000000000FFFF")));
Console.WriteLine(string.Format(formatter, HexStringToDouble("0000FFFFFFFFFFFF")));
Console.WriteLine(string.Format(formatter, HexStringToDouble("FFFFFFFFFFFFFFFF")));
Console.WriteLine(string.Format(formatter, HexStringToDouble("FFF0000000000000")));
Console.WriteLine(string.Format(formatter, HexStringToDouble("7FF0000000000000")));
Console.WriteLine(string.Format(formatter, HexStringToDouble("FFEFFFFFFFFFFFFF")));
Console.WriteLine(string.Format(formatter, HexStringToDouble("7FEFFFFFFFFFFFFF")));
Console.WriteLine(string.Format(formatter, HexStringToDouble(long.MinValue.ToString())));
Console.WriteLine(string.Format(formatter, HexStringToDouble(long.MaxValue.ToString())));
Console.ReadKey();
}
private static double HexStringToDouble(string hexString)
{
double dnumber = 0;
long number;
bool result = Int64.TryParse(hexString,
NumberStyles.HexNumber, CultureInfo.InvariantCulture,
out number);
dnumber=BitConverter.Int64BitsToDouble(number);
return dnumber;
}`
输出将为