Question

我在for循环中有以下代码。当它第一次通过时，运行得很好。然而，当它再次运行时，它会在cin.ignore之前停止，我必须先按Enter键才能输入输入。有什么理由呢？感谢。

cin.ignore(100, '\n');
string input;
getline(cin, input);

编辑：

以下是代码的全部内容：

请注意，矢量餐厅中有16个字符串。函数ifOddNumberOfRestaurants如下：

void ifOddNumberOfRestaurants(vector<string> restaurants){

cout << "To begin the tournament, please add one more restaurant to the list: ";
cin.ignore(1000, '\n');
string newRestaurant;
getline(cin, newRestaurant);

restaurants.push_back(newRestaurant);
}

有问题的代码：

else if ( option == 5 ) {

        int numberRestaurants = restaurants.size();

        int evenOrOdd = numberRestaurants % 2;

        if (evenOrOdd == 1){

            ifOddNumberOfRestaurants(restaurants);

        }

        vector<string> battleRestaurants(restaurants);

        int stop = 0;

        while ( stop == 0 ){

            double half = battleRestaurants.size()/2;
            int option1 = 0;
            int option2 = 1;
            int match = 1;

            for(int i = 0; i < half; i++){

                cout << "Match " << match << "/" << half << " --- " << battleRestaurants[option1] << " *OR* " << battleRestaurants[option2] << "? ";
                match++;
                cout << "\nBEFORE IGNORE\n";
                cin.ignore(100, '\n');
                cout << "\nAFTER IGNORE\n";
                string winner;
                getline(cin, winner);


                if ( winner == battleRestaurants[option1]){
                    battleRestaurants.erase(battleRestaurants.begin() + option2);
                }
                else if ( winner == battleRestaurants[option2]){
                    battleRestaurants.erase(battleRestaurants.begin() + option1);
                }

                option1++;
                option2++;

                cout << "Postion of i: " << i << "\nPosition of Option 1: " << option1 << "\nPosition of Option 2: " << option2 << "\n" << endl;

                printRestaurants(battleRestaurants);

            }

        }

    }

Answer 1

我认为你的问题是你有cin.ignore（100，＆＃39; \ n＆＃39;）;如果你不需要它删除它，你的代码应该可以正常工作。我只尝试了那个部分的一小段片段，它运行良好。 EX：`矢量餐厅;

int numberRestaurants = restaurants.size();

int evenOrOdd = numberRestaurants % 2;
for (int i = 0; i < 5; i++)
{
if (evenOrOdd == 1){
    cout << "To begin the tournament, please add one more restaurant to the list: ";
    //cin.ignore(100, '\n');
    string newRestaurant;
    getline(cin, newRestaurant);
    restaurants.push_back(newRestaurant);
   }
}

删除忽略这就是为什么你必须在接受任何其他内容之前按Enter键，因为它将忽略前100个字符或新的行，以先到者为准。

“cin.ignore”两次输入继续

1 个答案: