如何在Android中加速AutocompleteTextView?

时间:2014-03-25 20:11:11

标签: java android autocompletetextview trie

大家好我有一个扩展ArrayAdapter类的适配器并覆盖了一些Filterable方法。当用户在AutocompleteTextView内部输入时,我正在使用此适配器执行一些过滤。但是我看到如果你快速输入一下,过滤后的项目的升级变得非常慢。这是适配器类:

public class MunicipalitySearchAdapter extends ArrayAdapter<Municipality> {

private ArrayList<Municipality> municipalities;
private ArrayList<Municipality> allMunicipalities;
private ArrayList<Municipality> suggestedMunicipalities;
private int viewResourceId;

@SuppressWarnings("unchecked")
public MunicipalitySearchAdapter(Context context, int viewResourceId, ArrayList<Municipality> municipalities) {
    super(context, viewResourceId, municipalities);
    this.municipalities = municipalities;
    this.allMunicipalities = (ArrayList<Municipality>) this.municipalities.clone();
    this.suggestedMunicipalities = new ArrayList<Municipality>();
    this.viewResourceId = viewResourceId;
}

@Override
public View getView(int position, View convertView, ViewGroup parent) {
    View v = convertView;
    if (v == null) {
        LayoutInflater inflater = (LayoutInflater) getContext().getSystemService(Context.LAYOUT_INFLATER_SERVICE);
        v = inflater.inflate(this.viewResourceId, null);
    }
    Municipality municipality = municipalities.get(position);
    if (municipality != null) {
        TextView munNameTxtView = (TextView) v.findViewById(R.id.name);
        TextView proSignTxtView = (TextView) v.findViewById(R.id.sign);
        if (munNameTxtView != null) {
            munNameTxtView.setText(municipality.getName());
        }
        if (proSignTxtView != null) {
            proSignTxtView.setText(municipality.getProvinceSign());
        }
 }
    return v;
}


@Override 
public Filter getFilter() {
    return municipalityFilter;
}

Filter municipalityFilter = new Filter() {

    @Override
    public String convertResultToString(Object resultValue) {
        String str = ((Municipality) (resultValue)).getName();
        return str;
    }

    @Override
    protected FilterResults performFiltering(CharSequence constraint) {
        if (constraint != null) {
            suggestedMunicipalities.clear();
            for (Municipality municipality : allMunicipalities) {
                if (municipality.getName().toLowerCase(Locale.getDefault()).startsWith(constraint.toString().toLowerCase(Locale.getDefault()))) {
                    suggestedMunicipalities.add(municipality);
                }
            }
            FilterResults filterRes = new FilterResults();
            filterRes.values = suggestedMunicipalities;
            filterRes.count = suggestedMunicipalities.size();
            return filterRes;
        }
        else {
            return new FilterResults();
        }
    }

    @Override
    protected void publishResults(CharSequence constraint, FilterResults results) {
        if (results != null && results.count > 0) {
            @SuppressWarnings("unchecked")
            ArrayList<Municipality> filteredMunicipalities = (ArrayList<Municipality>) results.values;
            ArrayList<Municipality> supportMunicipalitiesList = new ArrayList<Municipality>();

            clear();
            for (Municipality mun : filteredMunicipalities) {
                supportMunicipalitiesList.add(mun);
            }
            Iterator<Municipality> municipalityIterator = supportMunicipalitiesList.iterator();
            while (municipalityIterator.hasNext()) {
                Municipality municipality = municipalityIterator.next();
                add(municipality);
            }
            notifyDataSetChanged();
        }           
    }
};
 }

我想问一下是否有人知道如何提高这种AutocompleteTextView的性能并使更新更快。我该怎么办?谢谢!

编辑:我创建了这个类: 顶点:     公共类Vertex {

private HashMap<Character, Vertex> vertexSons;
private List<Integer> wordsIndexList;
private List<Integer> prefixesIndexList;
private int wordsNumber;
private int prefixesNumber;

public Vertex() {
    vertexSons = new HashMap<Character, Vertex>();
    wordsIndexList = new ArrayList<Integer>();
    prefixesIndexList = new ArrayList<Integer>();
    wordsNumber = 0;
    prefixesNumber = 0;
}

public boolean hasWords() {
    if (wordsNumber > 0) {
        return true;
    }
    return false;
}

public boolean hasPrefixes() {
    if (prefixesNumber > 0) {
        return true;
    }
    return false;
}

public void addVertexSon(Character character) {
    vertexSons.put(character, new Vertex());
}

public void addIndexToWordsIndexList(int index) {
    wordsIndexList.add(index);
}

public void addIndexToPrefixesIndexList(int index) {
    prefixesIndexList.add(index);
}

public HashMap<Character, Vertex> getVertexSons() {
    return vertexSons;
}

public List<Integer> getWordsIndexList() {
    return wordsIndexList;
}

public List<Integer> getPrefixesIndexList() {
    return prefixesIndexList;
}

public int getWordsNumber() {
    return wordsNumber;
}

public int getPrefixesNumber() {
    return prefixesNumber;
}

public void increaseWordsNumber() {
    wordsNumber++;
}

public void increasePrefixesNumber() {
    prefixesNumber++;
}
}

并且Trie:

public class Trie {

private Vertex rootVertex;

public Trie(List<Trieable> objectList, Locale locale) {
    rootVertex = new Vertex();

    for (int i = 0; i<objectList.size(); i++) {
        String word = objectList.get(i).toString().toLowerCase(locale);
        addWord(rootVertex, word, i);
    }
}

public Vertex getRootVertex() {
    return rootVertex;
}

public void addWord(Vertex vertex, String word, int index) {
    if (word.isEmpty()) { 
        vertex.addIndexToWordsIndexList(index);
        vertex.increaseWordsNumber();
    }
    else {
        vertex.addIndexToPrefixesIndexList(index);
        vertex.increasePrefixesNumber();
        Character fChar = word.charAt(0);
        HashMap<Character, Vertex> vertexSons = vertex.getVertexSons();

        if (!vertexSons.containsKey(fChar)) {
            vertex.addVertexSon(fChar);
        }

        word = (word.length() == 1) ? "" : word.substring(1);
        addWord(vertexSons.get(fChar), word, index);
    }
}

public List<Integer> getWordsIndexes(Vertex vertex, String word) {
    if (word.isEmpty()) {
        return vertex.getWordsIndexList();
    }
    else {
        Character fChar = word.charAt(0);
        if (!(vertex.getVertexSons().containsKey(fChar))) {
            return null;
        }
        else {
            word = (word.length() == 1) ? "" : word.substring(1);
            return getWordsIndexes(vertex.getVertexSons().get(fChar), word);
        }
    }
}

public List<Integer> getPrefixesIndexes(Vertex vertex, String prefix) {
    if (prefix.isEmpty()) {
        return vertex.getWordsIndexList();
    }
    else {
        Character fChar = prefix.charAt(0);
        if (!(vertex.getVertexSons().containsKey(fChar))) {
            return null;
        }
        else {
            prefix = (prefix.length() == 1) ? "" : prefix.substring(1);
            return getWordsIndexes(vertex.getVertexSons().get(fChar), prefix);
        }
    }
}

}

并按照以下方式编辑了我的过滤器:

Filter municipalityFilter = new Filter() {



    @Override
    public String convertResultToString(Object resultValue) {
        String str = ((Municipality) (resultValue)).getName();
        return str;
    }

    @Override
    protected FilterResults performFiltering(CharSequence constraint) {

        if (constraint != null) {
            String constraintString = constraint.toString().trim();
            suggestedMunicipalities.clear();

            List<Integer> wordsIndexesList = municipalityTrie.getWordsIndexes(municipalityTrie.getRootVertex(), constraintString);
            for (int index : wordsIndexesList) {
                suggestedMunicipalities.add(allMunicipalities.get(index));
            }

            List<Integer> prefixesIndexesList = municipalityTrie.getPrefixesIndexes(municipalityTrie.getRootVertex(), constraintString);
            for (int index : prefixesIndexesList) {
                suggestedMunicipalities.add(allMunicipalities.get(index));
            }

            FilterResults filterRes = new FilterResults();
            filterRes.values = suggestedMunicipalities;
            filterRes.count = suggestedMunicipalities.size();
            return filterRes;
        }
        else {
            return new FilterResults();
        }
    }

    @Override
    protected void publishResults(CharSequence constraint, FilterResults results) {
        if (results != null && results.count > 0) {
            @SuppressWarnings("unchecked")
            ArrayList<Municipality> filteredMunicipalities = (ArrayList<Municipality>) results.values;
            ArrayList<Municipality> supportMunicipalitiesList = new ArrayList<Municipality>();

            clear();
            for (Municipality mun : filteredMunicipalities) {
                supportMunicipalitiesList.add(mun);
            }
            Iterator<Municipality> municipalityIterator = supportMunicipalitiesList.iterator();
            while (municipalityIterator.hasNext()) {
                Municipality municipality = municipalityIterator.next();
                add(municipality);
            }
            notifyDataSetChanged();
        }           
    }
};

现在,当我在此行输入AutoCompleteTextView时,我收到一个空指针警告:

List<Integer> wordsIndexesList = municipalityTrie.getWordsIndexes(municipalityTrie.getRootVertex(), constraintString);
            for (int index : wordsIndexesList) {
                suggestedMunicipalities.add(allMunicipalities.get(index));
            }

for(int index:wordsIndexesList)语句中。我该怎么办?谢谢!

1 个答案:

答案 0 :(得分:4)

您应该考虑使用trie,它非常适合自动完成。

这是一个人的样子:

enter image description here

当您获得更多字符时,您可以在树中进一步遍历,可能的选项数量将变得越来越小。

这比每次查看整个列表要快得多。


编辑:在反思我的回答之后,我认为更简单的解决方案就是使用任何类型的有序地图。 Checkout this answer for an example