Question

您好我一直在尝试使用我的jsp映射我的控制器但是它会出错并显示一个旧URL。我已多次尝试清理项目并更改了我的web.xml。

下面的

是我的xml：

<?xml version="1.0" encoding="UTF-8"?>
<web-app xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns="http://java.sun.com/xml/ns/javaee" xmlns:web="http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd" xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd" id="WebApp_ID" version="2.5">
  <display-name>Sphibernate</display-name>
  <welcome-file-list>
    <welcome-file>login.jsp</welcome-file>
    <welcome-file>index.htm</welcome-file>
    <welcome-file>index.jsp</welcome-file>
    <welcome-file>default.html</welcome-file>
    <welcome-file>default.htm</welcome-file>
    <welcome-file>default.jsp</welcome-file>
  </welcome-file-list>

 <servlet>
 <servlet-name>mvc-dispatcher </servlet-name>
 <servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
 <load-on-startup>1</load-on-startup>
 </servlet>

 <servlet-mapping>
 <servlet-name>mvc-dispatcher</servlet-name>
 <url-pattern>*.htm</url-pattern>
 </servlet-mapping>

</web-app>

以下是我的Controller类：

package com.lnt.controller;

import java.util.ArrayList;
import java.util.List;

import javax.servlet.http.HttpServletRequest;
import javax.servlet.http.HttpServletResponse;

import org.springframework.beans.factory.annotation.Autowired;
import org.springframework.stereotype.Controller;
import org.springframework.web.bind.annotation.RequestMapping;
import org.springframework.web.bind.annotation.RequestMethod;
import org.springframework.web.bind.annotation.RequestParam;
import org.springframework.web.servlet.ModelAndView;

import com.lnt.services.AuthenticateServices;

@Controller 
@RequestMapping("Login.htm")
public class LoginController {

    //@Autowired
     AuthenticateServices authenticateService = new AuthenticateServices();

    @RequestMapping(method=RequestMethod.POST)
    public ModelAndView processCredentials(HttpServletRequest req, HttpServletResponse res)

    {
        String userName =req.getParameter("userName") ;
        String password = req.getParameter("password");
        System.out.println("into login controller");
        String message = "Invalid credentials";
        List<String> userdetails = new ArrayList<String>();
        userdetails = authenticateService.verifyUserNameAndPassword(userName, password);
        if((userdetails.get(0))!= userName && (userdetails.get(1))!= password )
            {
            message = "welcome" + userName ;
        }
        return new ModelAndView("results", "message", message) ;
    }



    }

这是我的JSP：

<%@ page language="java" contentType="text/html; charset=ISO-8859-1"
    pageEncoding="ISO-8859-1"%>

<!DOCTYPE html PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN" "http://www.w3.org/TR/html4/loose.dtd">
<html>
<head>
<meta http-equiv="Content-Type" content="text/html; charset=ISO-8859-1">
<title>Insert title here</title>
</head>
<body>
<form action="Login.htm" method = "post">
<input type = "text" name = "userName" id = "userName">
<input type = "password" name = "password" id = "password">
<input type = "submit">
</form>
</body>
</html>

通过jsp调用我的动作时出现错误：

输入状态报告

message /Login.spring

description请求的资源（/Login.spring）不可用。

然而，没有网址映射为＆＃34; .spring＆＃34;在jsp或controller或web.xml中

@onepotato

这是我的应用程序上下文

<?xml version="1.0" encoding="UTF-8"?>
<beans xmlns="http://www.springframework.org/schema/beans"
    xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
    xsi:schemaLocation="http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans.xsd">

    <bean id="dataSourceBean" class="org.springframework.jdbc.datasource.DriverManagerDataSource">
        <property name="driverClassName" value="com.mysql.jdbc.Driver"></property>
        <property name="url" value="jdbc:mysql://localhost/springmvc"></property>
        <property name="username" value="root"></property>
        <property name="password" value="root"></property>        
    </bean> 
     <bean id="sessionFactoryBean" class="org.springframework.orm.hibernate3.LocalSessionFactoryBean">
        <property name="dataSource" ref="dataSourceBean"></property>
       <!--<property name="mappingResources">
            <value>com.lnt.Pojo/Login.hbm.xml</value>                   
        </property>-->
        <property name="hibernateProperties">
              <props>
                  <prop key="hibernate.dialect">org.hibernate.dialect.MySQL5Dialect</prop>
                  <prop key="hibernate.show_sql">true</prop>
              </props>
         </property>
    </bean>
    <bean id="hibernateTemplateBean" class="org.springframework.orm.hibernate3.HibernateTemplate">
        <property name="sessionFactory" ref="sessionFactoryBean"></property>
    </bean>
    <!--  <bean id="AuthenticateServiceBean" class="com.lnt.services.AuthenticateServices">
        <property name="hibernateTemplate" ref="hibernateTemplateBean"></property>
    </bean> -->

</beans>

以下是我的MVC Dispatcher

<?xml version="1.0" encoding="UTF-8"?>
<beans xmlns="http://www.springframework.org/schema/beans"
    xmlns:aop="http://www.springframework.org/schema/aop"
    xmlns:context="http://www.springframework.org/schema/context"
    xmlns:security="http://www.springframework.org/schema/security"
    xmlns:tx="http://www.springframework.org/schema/tx"
    xsi:schemaLocation="
        http://www.springframework.org/schema/aop http://www.springframework.org/schema/aop/spring-aop-3.0.xsd
        http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans-3.0.xsd
        http://www.springframework.org/schema/context http://www.springframework.org/schema/context/spring-context-3.0.xsd
        http://www.springframework.org/schema/security http://www.springframework.org/schema/security/spring-security-3.0.xsd
        http://www.springframework.org/schema/tx http://www.springframework.org/schema/tx/spring-tx-3.0.xsd"
    xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance">

    <context:component-scan base-package="com.lnt.controller"></context:component-scan>

    <bean id = "viewResolver" class="org.springframework.web.servlet.view.InternalResourceViewResolver">
    <property name="prefix">
    <value>/</value>
    </property>
    <property name="suffix">
    <value>.jsp</value>
    </property>

    </bean>
    </beans>

Answer 1

你只需要输入＆＃34; /登录＆＃34;而不是＆＃34; .html＆＃34;在请求映射中。这应该有效，如果它没有尝试将请求映射注释放在方法之上而不是类。

Answer 2

1.检查控制器是否通过从控制器打印控制台中的某些值来控制器。如果它打印，那么请求映射没有问题。

2.确保viewResolver bean下提供的jsp路径与服务器上jsp文件的路径匹配。

3.如果控制器没有到达控制器，则尝试从＆＃34; Login.htm＆＃34;更改@RequestMapping。到＆＃34; /Login.htm"因为我认为浏览器通常附加＆＃34; /＆＃34;在提交表格之前。

如果我遇到同样的问题，我会以上述方式解决。：）

Answer 3

<context-param>
    <param-name>contextConfigLocation</param-name>
    <param-value>classpath:Spring/servlet-context.xml,
    classpath:Spring/security-context.xml       
    </param-value>
</context-param>
<listener>
    <listener-class>org.springframework.web.context.ContextLoaderListener</listener-class>
</listener>
<servlet>
    <servlet-name>appServlet</servlet-name>
    <servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
    <init-param>
        <param-name>contextConfigLocation</param-name>
        <param-value></param-value>
    </init-param>
    <load-on-startup>1</load-on-startup>
</servlet>
<servlet-mapping>
    <servlet-name>appServlet</servlet-name>
    <url-pattern>/</url-pattern>
</servlet-mapping>
<filter>
    <filter-name>springSecurityFilterChain</filter-name>
    <filter-class>org.springframework.web.filter.DelegatingFilterProxy</filter-class>
</filter>
<filter-mapping>
    <filter-name>springSecurityFilterChain</filter-name>
    <url-pattern>/*</url-pattern>
</filter-mapping>
<error-page>
    <exception-type>java.lang.Throwable</exception-type>
    <location>/error.jsp</location>
</error-page>
<session-config>
    <session-timeout>60</session-timeout>
</session-config>

Spring MVC的Web.xml问题

3 个答案: