Question

我正在猜数字游戏，在结束时，我想告诉用户猜测正确答案需要多少次尝试。我还希望能够询问用户是否想再玩一次。我对此非常陌生，我只是在努力想弄清楚如何做到这一点。如果有人可以提供帮助，将不胜感激。

public void Play()
{
  HiLow hi = new HiLow();
  int number = hi.Number;
  int guess;

  for (guess = PromptForInt("\nEnter your guess! "); guess != number; guess = PromptForInt("\nEnter your guess! "))
  {
    if (guess < number)
    {
      Console.WriteLine("Higher");
    }
    else if (guess > number)
    {
      Console.WriteLine("Lower");
    }
  }
  Console.WriteLine("You win! {0} was the correct number!", number);
}

Answer 1

您只需要定义一个counter来存储用户尝试，然后您可以将您的for循环放在while(true)内，这样您就可以在for之后询问用户是否要再次播放循环：

while(true)
{
    int attempts = 0;
    for(...)
    {
         if (guess < number)
         {
             Console.WriteLine("Higher");
             attempts++;
         }
         else if (guess > number)
         {
             Console.WriteLine("Lower");
             attempts++;                  
         }
    }
    Console.WriteLine("You win! {0} was the correct number! your attempts: {1}", number, attempts);
    Console.WriteLine("Would you like to try again ? (y / n)");

    if(Console.ReadLine().ToLower() != "y") break;

}

Answer 2

这个怎么样

public void Play()
        {
           HiLow hi = new HiLow();
           int number = hi.Number;
           int guess;
   int attempts=0;

           for (guess = PromptForInt("\nEnter your guess! "); guess != number; guess = PromptForInt("\nEnter your guess! "))
           {
               if (guess < number)
               {
                   Console.WriteLine("Higher");
               }
               else if (guess > number)
               {
                   Console.WriteLine("Lower");                  
               }
attempts++;
           }
           Console.WriteLine("You win! {0} was the correct number!", number);
        }

然后您可以输出＆＃39;尝试＆＃39;告诉他们尝试了多少次。

此时，为了给他们再次播放的选项，最好不要单独播放Play（）并将重放的逻辑放入任何调用Play（因为Play是单个播放的一个很好的实现，不需要复杂化）

void PlayGame(){

  while(UserNoWantToQuit()){
    Play();
  }

 }

计算尝试次数，并要求用户再次播放循环。 C＃

2 个答案: