从串口读取双倍

时间:2014-04-01 09:21:23

标签: java serial-port double

我试图从串口读取一个双。 我可以在String中读取它,但是当我将String解析为Double时,结果没有意义,并且它与String不一样。

这是我的代码:

public void serialEvent(SerialPortEvent event){
        switch(event.getEventType()) {

            case SerialPortEvent.DATA_AVAILABLE:
                byte[] readBuffer = new byte[8];
                try {
                    while (inputStream.available()>0) {
                     int numBytes = inputStream.read(readBuffer);
                     String peso = new String (readBuffer, 0, numBytes, "UTF-8");
                     System.out.print(new String (readBuffer, 0, numBytes, "UTF-8"));
                    //double d = ByteBuffer.wrap(readBuffer).order(ByteOrder.LITTLE_ENDIAN ).getDouble();
                    //System.out.print(d);
                     m_dWeightBuffer = Double.parseDouble(peso);
                     System.out.print(m_dWeightBuffer);
                     }
                     //System.out.print(new String (readBuffer, 0, numBytes, "UTF-8"));
                    } catch (IOException ex) {}
                break;

        } 
    }

但现在,您知道如何将此字符串转换为Double?

System.out.print(new String (readBuffer, 0, numBytes, "UTF-8")); 输出:000.250

m_dWeightBuffer = Double.parseDouble(peso); System.out.print(m_dWeightBuffer); 输出:0.00.0250.0错误

System.out.println(new String (readBuffer, 0, numBytes, "UTF-8")); 输出:

0 0 0 .250

2 个答案:

答案 0 :(得分:3)

前言

服务器似乎正在串行端口上写入4个块,可能是64位字:

  1. 0
  2. 0
  3. 0
  4. 0.250
  5. 你正在读取64位的最大缓冲区(readBuffer.length * 8位),所以最后一个可能是:

      

    0011111111010000000000000000000000000000000000000000000000000000

    试一试:

            String s = "0011111111010000000000000000000000000000000000000000000000000000"; 
            double d = Double.longBitsToDouble(Long.parseLong(s,2));
            System.out.println(d); //-> 0.25
    

    至于现在没有错误

    答案

    可能你想要在一个点上处理所有4个块,所以你可以尝试以下 - 当然,很大程度上取决于我忽略的协议的语义:

        public void serialEvent(SerialPortEvent event){
                switch(event.getEventType()) {
    
                    case SerialPortEvent.DATA_AVAILABLE:
                        byte[] readBuffer = new byte[8];
                        String peso = "";
                        try {
                             while (inputStream.available()>0) {
                                 int numBytes = inputStream.read(readBuffer);
                                 peso += new String (readBuffer, 0, numBytes, "UTF-8");
                             }
    
                             m_dWeightBuffer = Double.parseDouble(peso);
    
                        } catch (IOException ex) {}
                        break;
    
                } 
        }
    

    也就是说,在读取所有数据后创建double。

答案 1 :(得分:2)

尝试这样做:

 public void serialEvent(SerialPortEvent event){
            switch(event.getEventType()) {

                case SerialPortEvent.DATA_AVAILABLE:
                    byte[] readBuffer = new byte[8];


                    try {
                         while (inputStream.available()>0) {
                             int numBytes = inputStream.read(readBuffer);
                             peso += new String (readBuffer, 0, numBytes, "UTF-8").replaceAll("\\s+","").replaceAll("\\n", "").replaceAll("\\r", "");

                         }
                    } catch (IOException ex) {}

                    break;

            } 
    }

Inicialize此SerialEvent方法的String peso OUTSIDE。

相关问题