ZF2和Doctrine 2将结果集转换为Array

时间:2014-04-03 14:36:13

标签: php arrays doctrine-orm zend-framework2

我使用Zend Framework 2和Doctrine 2.这是我的问题

以下命令返回对象数组

$results = $em->getRepository('MyProject\Domain\User')->find($id);

返回:

array (size=4)
  0 => 
    object(My\Entity\User)[3]
      private 'id' => int 1
      private 'firstName' => string 'joe' (length=3)
      private 'lastName' => string 'smith' (length=5)
  1 =>
      object(My\Entity\User)[3]
      private 'id' => int 1
      private 'firstName' => string 'joe' (length=3)
      private 'lastName' => string 'smith' (length=5)
  3 => 
    object(My\Entity\User)[3]
      private 'id' => int 1
      private 'firstName' => string 'joe' (length=3)
      private 'lastName' => string 'smith' (length=5)
  4 =>
      object(My\Entity\User)[3]
      private 'id' => int 1
      private 'firstName' => string 'joe' (length=3)
      private 'lastName' => string 'smith' (length=5)

我想将其转换为数组数组,如下所示:

array (size=4)
      0 =>
      array (size=3)
      ['id'] => int 1
      ['firstName'] => string 'joe' (length=3)
      ['lastName'] => string 'smith' (length=5)
      1 =>
      array (size=3)
      ['id'] => int 1
      ['firstName'] => string 'joe' (length=3)
      ['lastName'] => string 'smith' (length=5)
      2 =>
      array (size=3)
      ['id'] => int 1
      ['firstName'] => string 'joe' (length=3)
      ['lastName'] => string 'smith' (length=5)
      3 =>
      array (size=3)
      ['id'] => int 1
      ['firstName'] => string 'joe' (length=3)
      ['lastName'] => string 'smith' (length=5)

我尝试了以下内容:

$resultsArray = new \Doctrine\Common\Collections\ArrayCollection($results);
$resultsArray->toArray();

$resultsArray = new \Zend\Stdlib\ArrayObject($results);
$resultsArray->getArrayCopy();

两者都返回:

array (size=4)
  0 => 
    object(My\Entity\User)[3]
      private 'id' => int 1
      private 'firstName' => string 'joe' (length=3)
      private 'lastName' => string 'smith' (length=5)
  1 =>
      object(My\Entity\User)[3]
      private 'id' => int 1
      private 'firstName' => string 'joe' (length=3)
      private 'lastName' => string 'smith' (length=5)
  3 => 
    object(My\Entity\User)[3]
      private 'id' => int 1
      private 'firstName' => string 'joe' (length=3)
      private 'lastName' => string 'smith' (length=5)
  4 =>
      object(My\Entity\User)[3]
      private 'id' => int 1
      private 'firstName' => string 'joe' (length=3)
      private 'lastName' => string 'smith' (length=5)

我怎样才能做到这一点?建议的方法是什么?

3 个答案:

答案 0 :(得分:1)

最简单的形式,以下是您想要的

$qb = $em->getRepository('My\Entity\User')->createQueryBuilder('User');

$result = $qb->getQuery()->getArrayResult();

通常,您使用自定义存储库并将DQL查询添加为文档中描述的方法

http://docs.doctrine-project.org/en/2.0.x/tutorials/getting-started-xml-edition.html#entity-repositories

答案 1 :(得分:0)

传统上,我编写了一个自定义存储库类,并在其中调用getArrayResult()

        $dql = 'MYDQLHERE';
        $query = $this->getEntityManager()->createQuery($dql);
        $query->execute();
        $result =  $query->getArrayResult();

我相信你的另一种选择是定制补水模式,虽然我没有经验。 http://docs.doctrine-project.org/en/latest/reference/dql-doctrine-query-language.html#custom-hydration-modes

答案 2 :(得分:0)

另一种编码方式,我使用它:

//at the top of custom repository class
use Doctrine\Orm\Query;

//in the method
$dql = "SELECT u FROM MyProject\Domain\User u WHERE u.id = $id"
$query =  $entityManager->createQuery($dql);
$users = $query->getResult(Query::HYDRATE_ARRAY);
//knowing the code you provided, this should give you an array of four arrays
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