C ++：从文件中分隔名字和姓氏，用逗号分隔

Question

我将此作为文件：

Collins,Bill 80
Smith,Bart 75
Allen,Jim 82
Griffin,Jim 55
Stamey,Marty 90
Rose,Geri 78
Taylor,Terri 56
Johnson,Jill 77
Allison,Jeff 45
Looney,Joe 89
Wolfe,Bill 63
James,Jean 72
Weaver,Jim 77
Pore,Bob 91 
Rutherford,Greg 42
Javens,Renee 74
Harrison,Rose 58
Setzer,Cathy 93
Pike,Gordon 48
Holland,Beth 79

如您所见，姓氏和名字用逗号分隔。

现在我的代码中有这个：

ifstream inputFile;
inputFile.open ("students.txt");

string studentNames;            // Student names - Last name followed by first
int studentMarks = 0;           // Student mark for text/exam

// Read in data from students.txt
inputFile >> studentNames;
inputFile >> studentMarks;

// IF file has too much data, output WARNING
if (numElts >= NUM_NAMES)
{
    cout << "Error: File contains too many lines of data, check the file." << endl << endl;
}
else
{
    names[numElts] = studentNames;
    marks[numElts] = studentMarks;
    numElts++;
}

我想绕过这些逗号，我想将它存储为firstname，然后将其存储为姓氏，然后我将其合并为名称name = firstname " " last name。我该怎么办呢？

Answer 1

std::string::size_type commaPos = studentName.find(",");
std::string studentLastName = studentName.substr(0, commaPos);
std::string studentFirstName = studentName.substr(commaPos + 1);

Answer 2

使用此函数删除,并使用

之间的空格获取最后的名字

    string output;
    int position = studentNames.find(',');
    for(int i=position+1;i<studentNames.size();i++)
        output+=studentNames[i];
    output+=' ';
    for(int i=0;i<position;i++)
        output+=studentNames[i];
    studentNames = output;