Question

我有2个表，即table1和table2。两个表都有关系密钥mer_nbr。但是，表2中的条目是重复的，我们需要找到它们。

示例数据。表1

colA colB    colC    mer_nbr
1    01-Apr  03-Apr  1
2    02-Apr  03-Apr  2
3    03-Apr  04-Apr  3
4    04-Apr  05-Apr  4

Table2
colD colE    colF    mer_nbr delay
1    01-Apr  03-Apr  1       1
2    01-Apr  03-Apr  1       2
3    01-Apr  03-Apr  2       3
4    04-Apr  05-Apr  4       4

我需要的结果是mer_nbr 1，它在table2中有2个条目，具有不同的延迟但是相同的时间段，即01-Apr和03-Apr。

我尝试使用select table2.* from table1, table2 WHERE table2.colE = '01-APR-14' AND table2.colF = '03-APR-14'AND table1.mer_nbr = table2.mer_nbr;

但是，我也得到了mer_nbr = 2的详细信息。我只需要为mer_nbr 1显示2行的结果集。即

colD colE    colF    mer_nbr delay
1    01-Apr  03-Apr  1       1
2    01-Apr  03-Apr  1       2

请帮助。

Answer 1

你可以试试这个

with T as
(

select 1 as colD,to_date('01-04-2014','dd-mm-yyyy') as colE,to_date('03-04-2014','dd-mm-yyyy') as colF,1 as mem_nbr,1 as delay from dual
union
select 2 as colD,to_date('01-04-2014','dd-mm-yyyy') as colE,to_date('03-04-2014','dd-mm-yyyy') as colF,1 as mem_nbr,2 as delay from dual
union
select 3 as colD,to_date('01-04-2014','dd-mm-yyyy') as colE,to_date('03-04-2014','dd-mm-yyyy') as colF,2 as mem_nbr,3 as delay from dual
union
select 4 as colD,to_date('04-04-2014','dd-mm-yyyy') as colE,to_date('05-04-2014','dd-mm-yyyy') as colF,4 as mem_nbr,4 as delay from dual

)

select * from 
(
select colD,colE,colf,mem_nbr,delay,count(*) over(partition by cole,colf,mem_nbr) as cnt
from T
) where cnt>1

使用2个表查找重复条目

1 个答案: