Question

我正在尝试制作一个bash脚本 - 接收两个输入（只有两个） - 然后打印出两个数字之间的所有偶数 - 在任何可被7整除的数字旁边打印出橙色 - 在任何可被11整除的数字旁边打印出香蕉 - 在任何可被13整除的数字旁边打印出梨最后打印出一个声明“水果的痴迷是什么？”

它在这个编译器中工作正常（http://www.compileonline.com/execute_bash_online.php）但在Linux中它出现错误信息，说$ Input2不是公认的标识符，并且在最后一行之后有一个意外的文件结尾

    #!/bin/bash
     read -p "Type in Two integer inputs you want evaluated, followed by [ENTER]:" Input1 Input2
      if [ -z $Input1 ]; then
        echo "Please enter a valid first integer"
        read -r Input1 Input2
    exit 1
    fi
    if [ -z $Input2 ]; 
  then
        echo "Please enter a valid second integer"
        read Input2
    fi
    if [ $# -gt 2 ]; then
    echo "Too many numbers have been inputted"
    fi
  echo "You entered: $Input1,$Input2"
  echo "Here are all the even numbers between your two values:" 
  echo ""
  # if Input 1 is larger than Input 2
  while [ $((Input2)) -lt $Input1 ]; do
    if [ $((Input1 % 2)) -gt 0 ];then
  echo -en "$((Input1 = $Input1 - 1)) "
  else
  echo -en "$((Input1 = $Input1 - 2)) "
  fi
    if [ $((Input1 % 7)) -eq 0 ]; then
    echo -en "orange "
    fi
    if [ $((Input1 % 11)) -eq 0 ]; then
    echo -en "banana "
    fi
    if [ $((Input1 % 13)) -eq 0 ]; then
    echo -en "pear "
    fi
    echo
  done;

    while [ $((Input1)) -lt $Input2 ]; do
    if [ $((Input2 % 2)) -gt 0 ];then
    echo -en "$((Input2 = $Input2 - 1)) "
  else
    echo -en "$((Input2 = $Input2 - 2)) "
  fi

    if [ $((Input2 % 7)) -eq 0 ]; then
    echo -en "orange "
    fi
    if [ $((Input2 % 11)) -eq 0 ]; then
    echo -en "banana "
    fi
    if [ $((Input2 % 13)) -eq 0 ]; then
    echo -en "pear "
    fi
    echo
  done;

  echo "what is with the fruit obsession?"
  exit 0

Answer 1

使用dos2unix to convert windows样式的行终结符\r\n来* nix样式\n：

dos2unix fruit.sh

注意我在脚本上使用了反unix2dos，然后当我运行它时，我得到了相同的错误：

$ ./fruit.sh
Type in Two integer inputs you want evaluated, followed by [ENTER]:2 8
You entered: 2,8
Here are all the even numbers between your two values:

6 
4 
2 
what is with the fruit obsession?
$ unix2dos fruit.sh 
unix2dos: converting file fruit.sh to DOS format ...
$ ./fruit.sh
Type in Two integer inputs you want evaluated, followed by [ENTER]:1 2
': not a valid identifier `Input2
./fruit.sh: line 36: syntax error near unexpected token `done'
'/fruit.sh: line 36: `  done;
$

Answer 2

此代码不仅更短且更易于阅读，而且还应该更快地运行。它的输出与原始脚本几乎相同，例外处理输入。

当我在Linux机器上测试它时，我不知道它是如何在cygwin下运行的。

#!/bin/bash

repeat=yes
while [ $repeat = "yes" ]; do
    read -p "Type in Two integer inputs you want evaluated, followed by [ENTER]: " Input1 Input2 Input3
    repeat=no
    [ -z $Input2 ] && { echo "Incorect: Not Enough Inputs"; repeat=yes ;}
    [ ! -z $Input3 ] && { echo "Incorect: Too many inputs"; repeat=yes;}
done

echo -e "You entered: $Input1,$Input2\nHere are all the even numbers between your two values:"

if [ $Input1 -lt $Input2 ]; then
    larg=$Input1 ; small=$Input2
else
    larg=$Input2 ; small=$Input1
fi

while [ $larg -lt $small ]; do
    ((small % 2)) && { echo ; echo -en "$((small = $small - 1)) " ;}
    ((small % 7)) || echo -en "orange "
    ((small % 11)) || echo -en "banana "
    ((small % 13)) || echo -en "pear "
    small=$(($small - 1))
done
echo

bash脚本适用于在线编译器，但不适用于Linux

2 个答案: