我想编写一个程序,它将从文本文件中读取并使用结构存储文本文件中的内容并重新组合并打印出文本文件中的信息。但是我遇到了getline
的问题。我试着像这样写getline
getline(infile, info.name)
但它不起作用。我还包括<string>
和<cstring>
,但我仍然遇到像
错误C2664:'std :: basic_istream&lt; _Elem,_Traits&gt; &amp; std :: basic_istream&lt; _Elem,_Traits&gt; :: getline(_Elem *,std :: streamsize)' :无法将参数1从'int'转换为'char *'
和
错误C2664:'std :: basic_istream&lt; _Elem,_Traits&gt; &安培;的std :: basic_istream&LT; _Elem,_Traits&GT; ::函数getline(_Elem *,std :: streamsize,_Elem)':无法将参数1从'char [10] [80]'转换为'char *'
我打算打印出来的文本文件是以下文本
Isabella Chan新加坡共和国的天秤座23 - 10 - 1993年7月我希望在c ++方面做得很好我希望如此 christina grimmie将赢得声音我希望......左右
对于noob问题表示歉心,并提前致谢!
#include <iomanip>
#include <iostream>
#include <cstdlib>
#include <ctime>
#include <cctype>
#include <fstream>
#include <string>
using namespace std;
const int MAX = 80;
const int MAXNO = 10;
enum Zodiac
{
Aquarius, Pisces, Aries, Taurus,
Gemini, Cancer, Leo, Virgo,
Libra, Scorpio, Sagittarius, Capricorn
};
struct Date
{
Zodiac sign;
int day;
int month;
int year;
};
struct Student
{
char name [MAX];
char nationality [MAX];
Date birthDate;
int no; // no of other messages
char wishMessage [MAXNO][MAX];
// Feel free to add in more features
};
void myInfo (fstream&, char [], Student&);
// The above function reads information from the text file
// and store the information in a structure reference parameter
void printOut(Student);
int main()
{
fstream infile;
char fName[MAX];
Student info;
cout << "Enter your info file name: "
cin >> fName;
cout << endl;
myInfo(infile, fName, info);
printOut(info);
}
void myInfo (fstream& infile, char fName[], Student& info)
{
infile.open(fName, ios::in);
if(!infile)
{
cout << "Error file not found!" << endl;
exit(0);
}
infile.getline(info.name, MAX);
infile.getline(info.nationality,MAX);
infile << info.birthDate.sign
<< info.birthDate.day
<< info.birthDate.month
<< info.birthDate.year;
infile.getline(info.no, MAX);
infile.getline(info.wishMessage, MAXNO, MAX);
infile.close();
cout << "Successfully readed!" << endl;
}
void printOut(Student info)
{
cout << "My name is " << info.name << endl;
cout << "My nationality is " << info.nationality << endl;
cout << "My date of birth is " << info.birthDate.day
<< " " << info.birthDate.month << " "
<< info.birthDate.year << endl;
cout << "I am " << info.birthDate.sign << endl;
cout << "\n I have " << info.no << " wishes:" << endl;
}
答案 0 :(得分:0)
您似乎正在尝试使用getline读取非字符串,而按照documentation读取字符串。
将流中的字符作为未格式化的输入提取并将其作为c字符串存储到s中,直到提取的字符为分隔字符,或者已将n个字符写入s(包括终止空字符)。
以下是两条违规行:
infile.getline(info.no, MAX);
和
infile.getline(info.wishMessage, MAXNO, MAX);
前者读入int,后者读入字符串数组。
您需要先读取字符串,然后根据需要进行相应的转换操作。