Question

我将以下xml片段作为字符串：

String str ="<xs:user>userName</xs:user><xs:password>userPassword</xs:password>
<xs:address>addressString</xs:address>";

用xxxxxxx替换userPassword的最佳方法是什么？

编辑：xs（名称空间）可能会有所不同。

Answer 1

尝试使用：

String str2 = str.replaceFirst("<xs:password>.*?</xs:password>", "<xs:password>xxxxxxxxxx</xs:password>");`

Answer 2

这应该这样做。这是我现在能想到的最简单的解决方案。

public static void main(String[] args) {
    String str = "aaaaa<xs:password>userPassword</xs:password>bbbbbbbbbb";
    String newPassword = "test";
    String s2 = str.replaceAll("<xs:password>[^<]*</xs:password>", "<xs:password>" + newPassword + "</xs:password>");
    System.out.println(s2);
}

Answer 3

旧学校的字符串爬行方法是：

    String in =
            "<xs:user>userName</xs:user>" +
            "<xs:password>userPassword</xs:password>" +
            "<xs:address>addressString</xs:address>";

    int pwStart = in.indexOf("<xs:password>") + 13;
    int pwLen   = in.indexOf("</xs:password>") - pwStart;

    StringBuilder out = new StringBuilder();

    out.append(in.substring(0, in.indexOf("<xs:password>") + 13));
    for (int i = 0; i < pwLen; i++) {
        out.append("x");
    }
    out.append(in.substring(in.indexOf("</xs:password>")));

    System.out.printf("%s\n", in);
    System.out.printf("%s\n", out);

Answer 4

在Java中：

public static void replace(){

    String str =
            "<xs:user>userName</xs:user>" +
            "<xs:password>userPassword</xs:password>" +
            "<xs:address>addressString</xs:address>";

    String[] s = str.split("><");

    String[] t = s[1].split("password>");

    String[] a = t[1].split("</xs:");

    System.out.println(a[0]);

    String newS = s[0] + "><" + t[0] + "password>" + "YOUR XXXXXXX GOES HERE" + "</xs:" + a[1] + "><" + s[2];

    System.out.println(newS);

}

希望这有帮助。

java - 在两个模式字符串之间查找和替换子字符串

4 个答案: