Question

我知道这个例外之前被问了一百万次，我看到各个帖子说不同的建议，但对我来说没有任何作用。

我需要使用httpget从网址获取一些数据，并在我的网址中提供特定的ID。我的输出应该看起来像这个

{
"id": "35ZGXU7WQHFYY5BFTV6EACGEUS",
"createTime": "2014-04-11T12:52:26",
"updateTime": "2014-04-11T12:52:55",
"status": "Completed",
"transaction": {
    "amount": {
        "currencyCode": "GBP",
        "total": 7.47
    },
    "qrcode": "189e8dad99908745o7439f8ffabdfipp",
    "description": "This is the payment transaction description."
}
}

但由于某些内容出现此错误

04-11 18：24：14.655：E / STATUS_ERR（30067）：org.json.JSONException：java.lang.String类型的值com.mywallet.android.rest.MyWalletRestService$getStatus@41837fd0不能转换为JSONObject

我的代码如下

 String line = null;
        try{
            BufferedReader in = null;


            HttpGet request = new HttpGet();
            URI website = new URI(url);
            request.setURI(website);
            request.setHeader("Accept", "application/json");
            request.setHeader(AppConstants.PAYMENT_HEADER1, BEARER);
            request.setHeader(AppConstants.content_type, AppConstants.application_json);
            response = httpClient.execute(request);


            in = new BufferedReader(new InputStreamReader(response.getEntity().getContent(), "UTF-8"), 8);
            StringBuilder sb = new StringBuilder();

            while ((line = in.readLine()) != null)
            {
                sb.append(line + "\n");
            }

            result = sb.toString();
           JSONObject jObject = new JSONObject(toReturn);

            }

        if(jObject.has("error")){
            RES_STATUS      =   AppConstants.FAIL;
        }
        else{

             AppVariables.id                    =   jObject.getString(AppVariables.id_);
             AppVariables.createTime            =   jObject.getString(AppVariables.createTime_);
             AppVariables.updateTime            =   jObject.getString(AppVariables.updateTime_);
             AppVariables.status                =   jObject.getString(AppVariables.status_);             
             JSONObject oneObject               =   jObject.getJSONObject("transaction");
             JSONObject twoObject               =   oneObject.getJSONObject("amount");           
             AppVariables.total                 =   twoObject.getString("total");
             AppVariables.currencyCode          =   twoObject.getString("currencyCode");
             AppVariables.qrcode                =   oneObject.getString(AppVariables.qrcode_);
             AppVariables.description           =   oneObject.getString(AppVariables.description_);              

             MWLog.e("AppVariables.id", AppVariables.id);
             MWLog.e("AppVariables.createTime", AppVariables.createTime);
             MWLog.e("AppVariables.updateTime", AppVariables.updateTime);
             MWLog.e("AppVariables.status", AppVariables.status);
             MWLog.e("AppVariables.currencyCode", AppVariables.currencyCode);                
             MWLog.e("AppVariables.total", AppVariables.total);
             MWLog.e("AppVariables.qrcode", AppVariables.qrcode);
             MWLog.e("AppVariables.des", AppVariables.description);

             RES_STATUS                     =   AppConstants.SUCCESS;

             MWLog.e("BUYER", toReturn);
        }

Answer 1

使用此功能获取正确的json响应

public String getResponseBody(final HttpEntity entity) throws IOException, ParseException {

    if (entity == null) {
        throw new IllegalArgumentException("HTTP entity may not be null");
    }

    InputStream instream = entity.getContent();

    if (instream == null) {
        return "";
    }

    if (entity.getContentLength() > Integer.MAX_VALUE) {
        throw new IllegalArgumentException(

        "HTTP entity too large to be buffered in memory");
    }

    StringBuilder buffer = new StringBuilder();

    BufferedReader reader = new BufferedReader(new InputStreamReader(instream, HTTP.UTF_8));

    String line = null;
    try {
        while ((line = reader.readLine()) != null) {
            buffer.append(line.trim());
        }

    } finally {
        instream.close();
        reader.close();
    }
    return buffer.toString().trim();

}

如何使用？

result= getResponseBody(response.getEntity());

Answer 2

       result = sb.toString();
       JSONObject jObject = new JSONObject(toReturn);

不应该

       result = sb.toString();
       JSONObject jObject = new JSONObject(result);

您正在尝试将String转换为返回，其中包含无效的JSON数据。

Answer 3

这里Amount是一个JsonArray，你试图在json对象中强制它

JSONArray JsonArray2 = jsonobject.getJSONArray("amount");

试试这种方式

Jsonexception - 无法转换为JSONObject

3 个答案: