Question

我正在尝试列出处理大多数客户的代表

SELECT RTRIM(S.REP_FNAME) + ' ' + S.REP_LNAME AS [Representative], COUNT(C.REP_NUM) AS Customer(s) Per Rep]
FROM CUSTOMER C, SALESREP S 
WHERE S.REP_NUM = C.REP_NUM
GROUP BY RTRIM(S.REP_FNAME) + ' ' + S.REP_LNAME

我的查询返回：

代表客户每位代表
胡安佩雷斯3
理查德赫尔4
瓦莱丽凯撒4

注意* Richard和Valerie就是我想要的。它应该显示为两个记录

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Answer 1

 SELECT RTRIM(S.REP_FNAME) + ' ' + S.REP_LNAME AS [Representative], COUNT(C.REP_NUM) AS [Customer(s) Per Rep]
 FROM CUSTOMER C
 JOIN SALESREP S 
   ON S.REP_NUM = C.REP_NUM
 GROUP BY RTRIM(S.REP_FNAME) + ' ' + S.REP_LNAME 
 HAVING COUNT(*) = (SELECT COUNTS FROM (SELECT TOP(1) REP_NUM, COUNT(REP_NUM) AS COUNTS GROUP BY REP_NUM ORDER BY COUNT(REP_NUM) DESC ))

或者你可以使用你给它的名字。：

ORDER BY [Customer(s) Per Rep] DESC

或者对于不太复杂的方法：

SELECT TOP(1) RTRIM(S.REP_FNAME) + ' ' + S.REP_LNAME AS [Representative], COUNT(C.REP_NUM) AS [Customer(s) Per    Rep]
FROM CUSTOMER C, SALESREP S 
WHERE S.REP_NUM = C.REP_NUM
GROUP BY RTRIM(S.REP_FNAME) + ' ' + S.REP_LNAME 
ORDER BY [Customer(s) Per Rep] DESC

找到处理最多客户的代表

1 个答案: