我没有看到类似的问题,所以我要问一个新问题。我也尝试使用循环和数组,所以如果这是一个非常愚蠢的问题或非常糟糕的代码,请道歉。我能够用大约50行代码实现我想要的结果,但它更加不优雅(我基本上每个查询都是在硬编码的行中,而不是使用变量)。因此,我正在努力学习如何更整齐地编码,以提高效率。我可能会走错路......但
我有一个包含以下基本结构的表:
[id / username / email / content / side / category / rating]
Side可以是"是"或"不"和类别可以是"红色","蓝色"或"绿色"。这些在提交表格中受到限制。
我试图在循环中执行以下查询以获取所有必需的数据并将它们存储到php中的二维变量中:
$dialecticSides = array("yes","no");
$numberSides = 2;
$dialecticRow = array("red","blue","green");
$numberRows = 3;
$dialectic_queryString = $dialectic_mysqlQuery = $dialectic_sqlResult = $dialectic_totalRows = array();
for($x=0;$x<$numberSides;$x++) {
for ($y=0;$y<$numberRows;$y++) {
$dialectic_queryString[$x][$y] = "SELECT * FROM ". $dialectic_sqlTable ." WHERE side = '" . $dialecticSides[$x]. "' AND category = '". $dialecticRow[$y]."' ORDER BY rating DESC";
$dialectic_mysqlQuery[$x][$y] = mysql_query($dialectic_queryString[$x][$y], $commenting_conn) or die(mysql_error());
$dialectic_sqlResult[$x][$y] = mysql_fetch_assoc($dialectic_mysqlQuery[$x][$y]);
$dialectic_totalRows[$x][$y] = mysql_num_rows($dialectic_sqlResult[$x][$y]);
var_dump($dialectic_sqlResult);
}
}
我想要的输出是这样的:
Array
(
[0] => Array
(
[0] => Array
(
all the comments which are in row 0 (yes) and side 0 (red)
)
[1] => Array
(
all the comments which are in row 0 (yes) and side 1 (blue)
)
[2] => Array
(
all the comments which are in row 0 (yes) and side 2 (green)
)
)
[1] => Array
(
[0] => Array
(
all the comments which are in row 1 (no) and side 0 (red)
)
[1] => Array
(
all comments which are in row 1 (no) and side 1 (blue)
)
[2] => Array
(
all the comments which are in row 1 (no) and side 2 (green)
)
)
)
基本上,如果我想知道我所做的事情是否有任何意义,或者我是否应该放弃并返回将查询硬编码到不同的结果变量。
我的查询失败 - 查询的输出为空。我究竟做错了什么?提前谢谢!
====解决它====
for($x=0;$x<$numberSides;$x++) {
for ($y=0;$y<$numberRows;$y++) {
$queryString[$x][$y] = "SELECT * FROM comments WHERE topic_id = '{$topicid}' AND side = '{$x}' AND row = '{$y}'";
$result[$x][$y] = mysqli_query($db_connection,$queryString[$x][$y]) or die(mysqli_error($db_connection));
while($eachcomment = mysqli_fetch_assoc($result[$x][$y])) {
$array[$x][$y][] = $eachcomment;
}
}
答案 0 :(得分:0)
您不希望将查询等放入数组中 你只想要一个查询 定义2个数组以获取输出行和列:
$rowarray = array("yes" => 0, "no" => 1); // 2 rows?
$colarray = array("red" => 0, "blue" => 1, "green" => 2); // 3 cols?
初始化输出数组:
$outputarray = array(array('', '', ''), array('', '', ''));
从您的查询中获取$ result。
SELECT * FROM table
(没有WHERE子句)
然后处理结果:
while (($qrow = mysql_fetch_assoc($result))<>NULL) {
$ qrow是一个关联数组:'side'=&gt; '是','类别'=&gt; '红'等。
对于每个qrow,获取输出行和col:
$row = $rowarray[$qrow['side']];
$col = $colarray[$qrow['category']]
此时你可以在$ outputarray中积累你想要的东西:
$outputarray[$row][$col] .= $qrow['comments'];
这是“while”循环的结束:
}