我有hh:mm的时间，用户必须以该格式输入。
但是，我想比较时间（例如11:22）是在上午10点到下午6点之间吗？但是我如何比较呢？
答案 0 :(得分：52)
Java（还）没有一个好的内置Time类（它有一个用于JDBC查询，但这不是你想要的）。
一种选择是使用JodaTime API及其LocalTime类。
只使用内置的Java API，您就会遇到java.util.Date。您可以使用SimpleDateFormat来解析时间，然后使用Date比较函数来查看它是在其他时间之前还是之后：
SimpleDateFormat parser = new SimpleDateFormat("HH:mm");
Date ten = parser.parse("10:00");
Date eighteen = parser.parse("18:00");
try {
Date userDate = parser.parse(someOtherDate);
if (userDate.after(ten) && userDate.before(eighteen)) {
...
}
} catch (ParseException e) {
// Invalid date was entered
}
或者您可以使用一些字符串操作，也许是正则表达式来提取小时和分钟部分，将它们转换为数字并进行数值比较：
Pattern p = Pattern.compile("(\d{2}):(\d{2})");
Matcher m = p.matcher(userString);
if (m.matches() ) {
String hourString = m.group(1);
String minuteString = m.group(2);
int hour = Integer.parseInt(hourString);
int minute = Integer.parseInt(minuteString);
if (hour >= 10 && hour <= 18) {
...
}
}
这完全取决于你想要完成的任务。
答案 1 :(得分：13)
使用Java 8+，您可以使用新的Java时间API：
解析时间：
LocalTime time = LocalTime.parse("11:22")
进行日期比较，您有LocalTime::isBefore和LocalTime::isAfter - 请注意这些方法是严格的
所以问题就像：
public static void main(String[] args) {
LocalTime time = LocalTime.parse("11:22");
System.out.println(isBetween(time, LocalTime.of(10, 0), LocalTime.of(18, 0)));
}
public static boolean isBetween(LocalTime candidate, LocalTime start, LocalTime end) {
return !candidate.isBefore(start) && !candidate.isAfter(end); // Inclusive.
}
对于包容性开始但是独占结束（半开），请使用此行。
return !candidate.isBefore(start) && candidate.isBefore(end); // Exclusive of end.
答案 2 :(得分：5)
示例：
import java.util.*;
import java.lang.Object;
import java.text.Collator;
public class CurrentTime{
public class CurrentTime
{
public static void main( String[] args )
{
Calendar calendar = new GregorianCalendar();
String am_pm;
int hour = calendar.get( Calendar.HOUR );
int minute = calendar.get( Calendar.MINUTE );
// int second = calendar.get(Calendar.SECOND);
if( calendar.get( Calendar.AM_PM ) == 0 ){
am_pm = "AM";
if(hour >=10)
System.out.println( "welcome" );
}
else{
am_pm = "PM";
if(hour<6)
System.out.println( "welcome" );
}
String time = "Current Time : " + hour + ":" + minute + " " + am_pm;
System.out.println( time );
}
}
答案 3 :(得分：4)
从您的陈述中，您似乎只想写：
if (10 >= hh && hh < 18) {
...
}
如果您已经有时间，这是微不足道的。但你肯定还在问别的什么吗？
答案 4 :(得分：2)
以下假设您的小时和分钟分别存储为名为hh和mm的变量中的整数。
if ((hh > START_HOUR || (hh == START_HOUR && mm >= START_MINUTE)) &&
(hh < END_HOUR || (hh == END_HOUR && mm <= END_MINUTE))) {
...
}
答案 5 :(得分：2)
import java.util.Calendar;
Calendar cal = Calendar.getInstance();
int currentHour = cal.get(Calendar.HOUR);
if (currentHour > 10 && currentHour < 18) {
//then rock on
}
答案 6 :(得分：2)
package javaapplication4;
import java.text.*;
import java.util.*;
/**
*
* @author Stefan Wendelmann
*/
public class JavaApplication4
{
private static SimpleDateFormat sdf = new SimpleDateFormat("HH:mm:ss.SSS");
/**
* @param args the command line arguments
*/
public static void main(String[] args) throws ParseException
{
SimpleDateFormat parser = new SimpleDateFormat("dd.MM.YYYY HH:mm:ss.SSS");
Date before = parser.parse("01.10.1990 07:00:00.000");
Date base = parser.parse("01.10.1990 08:00:00.000");
Date after = parser.parse("01.10.1990 09:00:00.000");
printCompare(base, base, "==");
printCompare(base, before, "==");
printCompare(base, before, "<");
printCompare(base, after, "<");
printCompare(base, after, ">");
printCompare(base, before, ">");
printCompare(base, before, "<=");
printCompare(base, base, "<=");
printCompare(base, after, "<=");
printCompare(base, after, ">=");
printCompare(base, base, ">=");
printCompare(base, before, ">=");
}
private static void printCompare (Date a, Date b, String operator){
System.out.println(sdf.format(b)+"\t"+operator+"\t"+sdf.format(a)+"\t"+compareTime(a, b, operator));
}
protected static boolean compareTime(Date a, Date b, String operator)
{
if (a == null)
{
return false;
}
try
{
//Zeit aus Datum holen
// The Magic happens here i only get the Time out of the Date Object
SimpleDateFormat parser = new SimpleDateFormat("HH:mm:ss.SSS");
a = parser.parse(parser.format(a));
b = parser.parse(parser.format(b));
}
catch (ParseException ex)
{
System.err.println(ex);
}
switch (operator)
{
case "==":
return b.compareTo(a) == 0;
case "<":
return b.compareTo(a) < 0;
case ">":
return b.compareTo(a) > 0;
case "<=":
return b.compareTo(a) <= 0;
case ">=":
return b.compareTo(a) >= 0;
default:
throw new IllegalArgumentException("Operator " + operator + " wird für Feldart Time nicht unterstützt!");
}
}
}
run:
08:00:00.000 == 08:00:00.000 true
07:00:00.000 == 08:00:00.000 false
07:00:00.000 < 08:00:00.000 true
09:00:00.000 < 08:00:00.000 false
09:00:00.000 > 08:00:00.000 true
07:00:00.000 > 08:00:00.000 false
07:00:00.000 <= 08:00:00.000 true
08:00:00.000 <= 08:00:00.000 true
09:00:00.000 <= 08:00:00.000 false
09:00:00.000 >= 08:00:00.000 true
08:00:00.000 >= 08:00:00.000 true
07:00:00.000 >= 08:00:00.000 false
BUILD SUCCESSFUL (total time: 0 seconds)
答案 7 :(得分：2)
首先创建3个日历对象，仅设置您的时间，小时和分钟。
然后获得该时间的GMT毫秒并简单地进行比较。
实施例。
Calendar chechDateTime = Calendar.getInstance();
chechDateTime.set(Calendar.MILLISECOND, 0);
chechDateTime.set(Calendar.SECOND, 0);
chechDateTime.set(Calendar.HOUR, 11);
chechDateTime.set(Calendar.MINUTE, 22);
Calendar startDateTime = Calendar.getInstance();
startDateTime.set(Calendar.MILLISECOND, 0);
startDateTime.set(Calendar.SECOND, 0);
startDateTime.set(Calendar.HOUR, 10);
startDateTime.set(Calendar.MINUTE, 0);
Calendar endDateTime = Calendar.getInstance();
endDateTime.set(Calendar.MILLISECOND, 0);
endDateTime.set(Calendar.SECOND, 0);
endDateTime.set(Calendar.HOUR, 18);
endDateTime.set(Calendar.MINUTE, 22);
long chechDateTimeMilliseconds=chechDateTime.getTime().getTime();
long startDateTimeMilliseconds=startDateTime.getTime().getTime();
long endDateTimeMilliseconds=endDateTime.getTime().getTime();
System.out.println("chechDateTime : "+chechDateTimeMilliseconds);
System.out.println("startDateTime "+startDateTimeMilliseconds);
System.out.println("endDateTime "+endDateTimeMilliseconds);
if(chechDateTimeMilliseconds>=startDateTimeMilliseconds && chechDateTimeMilliseconds <= endDateTimeMilliseconds ){
System.out.println("In between ");
}else{
System.out.println("Not In between ");
}
输出将如下所示：
chechDateTime : 1397238720000
startDateTime 1397233800000
endDateTime 1397263920000
In between
答案 8 :(得分：1)
我正在以这种格式使用这个类的时间“hh：mm：ss”你可以使用它与“hh：mm：00”（零秒）作为你的例子。这是完整的代码。它具有比较和功能之间，还检查时间格式（如果时间无效并抛出TimeException）。希望您可以使用它或根据您的需要进行修改。
时间等级：
package es.utility.time;
import java.util.regex.Matcher;
import java.util.regex.Pattern;
/**
*
* @author adrian
*/
public class Time {
private int hours; //Hours of the day
private int minutes; //Minutes of the day
private int seconds; //Seconds of the day
private String time; //Time of the day
/**
* Constructor of Time class
*
* @param time
* @throws TimeException if time parameter is not valid
*/
public Time(String time) throws TimeException {
//Check if valid time
if (!validTime(time)) {
throw new TimeException();
}
//Init class parametars
String[] params = time.split(":");
this.time = time;
this.hours = Integer.parseInt(params[0]);
this.minutes = Integer.parseInt(params[1]);
this.seconds = Integer.parseInt(params[2]);
}
/**
* Constructor of Time class
*
* @param hours
* @param minutes
* @param seconds
* @throws TimeException if time parameter is not valid
*/
public Time(int hours, int minutes, int seconds) throws TimeException {
//Check if valid time
if (!validTime(hours, minutes, seconds)) {
throw new TimeException();
}
this.time = timeToString(hours, minutes, seconds);
this.hours = hours;
this.minutes = minutes;
this.seconds = seconds;
}
/**
* Checks if the sting can be parsed as time
*
* @param time (correct from hh:mm:ss)
* @return true if ok <br/> false if not ok
*/
private boolean validTime(String time) {
String regex = "([01]?[0-9]|2[0-3]):[0-5][0-9]:[0-5][0-9]";
Pattern p = Pattern.compile(regex);
Matcher m = p.matcher(time);
return m.matches();
}
/**
* Checks if the sting can be parsed as time
*
* @param hours hours
* @param minutes minutes
* @param seconds seconds
* @return true if ok <br/> false if not ok
*/
private boolean validTime(int hours, int minutes, int seconds) {
return hours >= 0 && hours <= 23 && minutes >= 0 && minutes <= 59 && seconds >= 0 && seconds <= 59;
}
/**
* From Integer values to String time
*
* @param hours
* @param minutes
* @param seconds
* @return String generated from int values for hours minutes and seconds
*/
private String timeToString(int hours, int minutes, int seconds) {
StringBuilder timeBuilder = new StringBuilder("");
if (hours < 10) {
timeBuilder.append("0").append(hours);
} else {
timeBuilder.append(hours);
}
timeBuilder.append(":");
if (minutes < 10) {
timeBuilder.append("0").append(minutes);
} else {
timeBuilder.append(minutes);
}
timeBuilder.append(":");
if (seconds < 10) {
timeBuilder.append("0").append(seconds);
} else {
timeBuilder.append(seconds);
}
return timeBuilder.toString();
}
/**
* Compare this time to other
*
* @param compare
* @return -1 time is before <br/> 0 time is equal <br/> time is after
*/
public int compareTime(Time compare) {
//Check hours
if (this.getHours() < compare.getHours()) { //If hours are before return -1
return -1;
}
if (this.getHours() > compare.getHours()) { //If hours are after return 1
return 1;
}
//If no return hours are equeal
//Check minutes
if (this.getMinutes() < compare.getMinutes()) { //If minutes are before return -1
return -1;
}
if (this.getMinutes() > compare.getMinutes()) { //If minutes are after return 1
return 1;
}
//If no return minutes are equeal
//Check seconds
if (this.getSeconds() < compare.getSeconds()) { //If minutes are before return -1
return -1;
}
if (this.getSeconds() > compare.getSeconds()) { //If minutes are after return 1
return 1;
}
//If no return seconds are equeal and return 0
return 0;
}
public boolean isBetween(Time before, Time after) throws TimeException{
if(before.compareTime(after)== 1){
throw new TimeException("Time 'before' is after 'after' time");
}
//Compare with before and after
if (this.compareTime(before) == -1 || this.compareTime(after) == 1) { //If time is before before time return false or time is after after time
return false;
} else {
return true;
}
}
public int getHours() {
return hours;
}
public void setHours(int hours) {
this.hours = hours;
}
public int getMinutes() {
return minutes;
}
public void setMinutes(int minutes) {
this.minutes = minutes;
}
public int getSeconds() {
return seconds;
}
public void setSeconds(int seconds) {
this.seconds = seconds;
}
public String getTime() {
return time;
}
public void setTime(String time) {
this.time = time;
}
/**
* Override the toString method and return all of the class private
* parameters
*
* @return String Time{" + "hours=" + hours + ", minutes=" + minutes + ",
* seconds=" + seconds + ", time=" + time + '}'
*/
@Override
public String toString() {
return "Time{" + "hours=" + hours + ", minutes=" + minutes + ", seconds=" + seconds + ", time=" + time + '}';
}
}
TimeException类：
package es.utility.time;
/**
*
* @author adrian
*/
public class TimeException extends Exception {
public TimeException() {
super("Cannot create time with this params");
}
public TimeException(String message) {
super(message);
}
}
答案 9 :(得分：1)
String timeRange = "12:24-13:24";
String[] timeR = timeRange.trim().split("-");
// java 8
LocalTime start = LocalTime.parse(timeR[0].trim());
LocalTime end = LocalTime.parse(timeR[1].trim());
LocalTime current = LocalTime.now();
LocalTime currentHM = LocalTime.parse(current.getHour()+":"+current.getMinute());
if(!currentHM.isBefore(start) && !currentHM.isAfter(end)) {
return true;
}else {
return false;
}
答案 10 :(得分：0)
您可以使用Java Date类中的compareTo（）方法
public int result = date.compareTo(Date anotherDate);
返回值：该函数提供以下指定的三个返回值：
如果参数Date等于此Date，则返回值0。 如果此Date在Date参数之前，则返回小于0的值。 如果此Date在Date参数之后，则返回大于0的值。