Question

SELECT ui.* 
FROM users_table as ui 
WHERE ui.id 
IN 
(
SELECT Group_concat
(REPLACE
(REPLACE
(REPLACE(ac.user_id,',,','-'),',',''),'-',',')) AS au_users 
FROM email_access as uu 
LEFT JOIN bill_authorizationcodes AS ac 
ON ac.customer_id = uu.cust_id 
WHERE uu.user_id = 2 
AND ac.user_id !=""
)

它没有选择所有的ID细节...... 它只选择第一个id ....

Answer 1

您使用了错误的方法。 In不希望带有逗号分隔值的字符串，而是值列表。只需使用

SELECT ui.* FROM users_table as ui 
WHERE ui.id IN (
    SELECT ac.user_id 
    FROM email_access as uu 
    LEFT JOIN bill_authorizationcodes AS ac ON ac.customer_id = uu.cust_id 
    WHERE uu.user_id = 2 AND ac.user_id !="")

如何在IN（）函数内部使用group_concat？

1 个答案: