Question

我有一个小问题。

我尝试使用推送通知来控制View Controller。

然而，我来到那里，新的＆＃34;页面＆＃34;没开。如果我发送相同但有一个动作按钮它可以工作。

谢谢你，Chris

AppDelegate.m

RootViewController *rootViewController = (RootViewController*)self.window.rootViewController;
[rootViewController openLinkNews];

RootViewController.m

- (void)awakeFromNib {
   self.contentViewController = [self.storyboard instantiateViewControllerWithIdentifier:@"contentController"];
   self.menuViewController = [self.storyboard instantiateViewControllerWithIdentifier:@"menuController"];
} 

-(void)openLinkNews {
   NewsTab *theLink = [[NewsTab alloc] init];
   [theLink openNewsPerLink];    
}

NewsTab.m

-(void)openNewsPerLink{
   NSLog(@"You are here!");

   dbConnect = [[DbConnect alloc] init];
   getNewsLast = [dbConnect getNewsLast];
   DbConnect *news = [getNewsLast objectAtIndex:0];

   NewsTab * infoController = [self.storyboard instantiateViewControllerWithIdentifier:@"NewsOpenViewController"];
   NewsOpen *detailViewController = (NewsOpen *) infoController;
   detailViewController.NewsHeadline = news.NewsHeadline;
   detailViewController.NewsInformation = news.NewsInformation;
   detailViewController.NewsFrom = news.NewsFrom;
   detailViewController.NewsDate = news.NewsDate;
   [self.navigationController pushViewController:infoController animated:YES];
}



-(IBAction)ButtonTest:(id)sender {
    [self openNewsPerLink];
}

Answer 1

您是从您的应用代表发布的代码，但是该方法是什么？

应用代理可以检索有关通知的信息，并使用其- (void)application:(UIApplication *)application didReceiveRemoteNotification:(NSDictionary *)userInfo方法对其进行响应。从那里你可以做任何你想做的事情，并使用通知来告知你的决定。

请参阅UIApplicationDelegate protocol reference

使用Link从AppDelegate打开Viewcontroller

1 个答案: