日期计算总天数

Question

我有这个代码，对于某些日期工作正常，我不明白为什么，下面的代码应该计算总天数。如果我选择leavefrom = 2014-04-21和leaveto = 2014-05-02，它总共给我8天，但应该是9天9天。

这是日历： -

    function total_day($leavefrom, $leaveto){
        $start_date=strtotime($leavefrom);
        $cur_day=$start_date;
        $end_day=strtotime($leaveto);
        $count=0;

        $holiday=array("2014-05-01"=>"Labour Day", "2014-08-31"=>"Independence Day", "2014-12-25"=>"Christmas");

        while(1){

            //echo date("Y/m/d", $cur_day)."<br/>";
            $cur_day=$cur_day +(3600*24);
            //echo $count."S--".date("Y-m-d", $cur_day)."<-----E--".$end_day;


            $day_of_week=date('w', $cur_day);
            //echo "day_of_week-----".$day_of_week."<br/>";
            if ($day_of_week == 0 || $day_of_week == 6) {
                //No Operation
            }else if(array_key_exists(date("Y-m-d", $cur_day), $holiday)){
                //echo "Holiday because of ".$holiday[date("Y-m-d", $cur_day)];
            }else{
                $count++;
            }
            //echo "Total day--".$count."<br/><br/>";

            if(($cur_day==($end_day+(3600*24)))||($cur_day>$end_day)){
                break;
            }

        }
        //$count = $count + 1;
        return $count;

    }

$totaldays = total_day($leavefrom, $leaveto);

Answer 1

我看到没有错误。从2014-04-21到2014-05-02有11天，其中2个周末和1个假期（2014-05-01）。从而制作11 days - 3 days = 8 days

但是如果你想包括开始日期。然后你可以使用它：

while(1){       
    if($cur_day>$end_day){
        break;
    }
    $day_of_week=date('l', $cur_day);
    if (in_array($day_of_week,array('Saturday','Sunday'))) {
        // NO operation
    }else if(array_key_exists(date("Y-m-d", $cur_day), $holiday)){
        // NO operation
    }else{
        $count++;
    }
    $cur_day=$cur_day +(3600*24);

}