我在网上搜索了很多,但没有找到有用的线索。
我的本地计算机上有一个websocket服务器和一个Web服务器。
当客户端使用浏览器API' new WebSocket(" ws:// localhost")'连接到它时,我需要将$ _SESSION数据传递给websocket服务器。 (请求使用反向代理发送到websocket,反向代理在接收带有“升级”标头的请求时知道它。
重点是客户端成功连接到ws服务器,但我需要使用HTTP Web服务器设置的$ _SESSION变量恢复其SESSION数据。
实际上我的情况是这样的(我正在使用Ratchet库):
use Ratchet\Server\IoServer;
use Ratchet\Http\HttpServer;
use Ratchet\WebSocket\WsServer;
use MyApp\MyAppClassChat;
require dirname(__DIR__) . '/vendor/autoload.php';
$server = IoServer::factory(new HttpServer(new WsServer(new MyAppClass())), 8080);
$server->run();
MyAppClass非常简单:
<?php
namespace MyAppClass;
use Ratchet\MessageComponentInterface;
use Ratchet\ConnectionInterface;
class MyAppClass implements MessageComponentInterface {
protected $clients;
public function __construct() {
$this->clients = new \SplObjectStorage;
}
public function onOpen(ConnectionInterface $conn) {
/* I would like to put recover the session infos of the clients here
but the session_start() call returns an empty array ($_SESSION variables have been previuosly set by the web server)*/
session_start();
var_dump($_SESSION) // empty array...
echo "New connection! ({$conn->resourceId})\n";
}
public function onMessage(ConnectionInterface $from, $msg) {
$numberOfReceivers = count($this->clients) -1;
echo sprintf('Connection %d sending message "%s" to %d other connection%s' . "\n", $from->resourceId, $msg,
$numberOfReceivers, $numberOfReceivers == 1 ? '' : 's');
$this->clients->rewind();
while ($this->clients->valid())
{
$client = $this->clients->current();
if ($client !== $from) {
$client->send($msg);
}
$this->clients->next();
}
}
public function onClose(ConnectionInterface $conn) {
$this->clients->detach($conn);
echo "Connection {$conn->resourceId} has disconnected\n";
}
public function onError(ConnectionInterface $conn, \Exception $e) {
echo "An error has occurred: {$e->getMessage()}\n";
$conn->close();
}
}
有没有办法用我的实际布局做到这一点,或者我应该配置apache才能使用 mod_proxy_wstunnel模块?
感谢您的帮助!!!
答案 0 :(得分:12)
当其他StackOverflow回答显示(Ratchet without Symfony session,Starting a session within a ratchet websocket connection)时,无法直接在Apache和Ratchet进程之间共享$ _SESSION变量。但是,可以启动与Apache服务器的会话,然后访问Ratchet代码中的会话cookie。
Apache服务器的index.html启动会话:
<?php
// Get the session ID.
$ses_id = session_id();
if (empty($ses_id)) {
session_start();
$ses_id = session_id();
}
?><!DOCTYPE html> ...
Ratchet MessageComponentInterface代码访问会话令牌:
public function onMessage(ConnectionInterface $from, $msg) {
$sessionId = $from->WebSocket->request->getCookies()['PHPSESSID'];
# Do stuff with the token...
}
一旦两个服务器都知道用户的会话令牌,他们就可以使用令牌通过MySQL数据库共享信息(这就是我所做的):
# Access session data from a database:
$stmt = $this->mysqli->prepare("SELECT * FROM users WHERE cookie=?");
$stmt->bind_param('s', $sessionId);
$stmt->execute();
$result = $stmt->get_result();
或者,您可以进行更奇特的进程间通信:
# Ratchet server:
$opts = array(
'http'=>array(
'method'=>'GET',
'header'=>"Cookie: PHPSESSID=$sessionId\r\n"
)
);
$context = stream_context_create($opts);
$json = file_get_contents('http://localhost:80/get_session_info.php', false, $context);
$session_data = json_decode($json);
# Apache server's get_session_info.php
# Note: restrict access to this path so that remote users can't dump
# their own session data.
echo json_encode($_SESSION);
答案 1 :(得分:1)
这可能看起来有点笨拙,但这是我想出如何实现这一点的唯一方法。
假设您已经知道目录和 sessionId,您可以直接使用 session_encode()
, session_decode()
从会话文件中读取数据,如下所示。我的会话文件以 sess_
为前缀,其他人可能不是这样,所以请记住这一点。请注意,这将在从会话文件中提取变量后保存并恢复任何现有的 $_SESSION
数据:
$contents = file_get_contents($sessionDir . 'sess_' . $sessionId);
$sessionData = $this->decodeSession($contents);
return $sessionData;
private function decodeSession($sessionString)
{
$currentSession = session_encode();
foreach ($_SESSION as $key => $value){
unset($_SESSION[$key]);
}
session_decode($sessionString);
$sessionVariables = $_SESSION;
foreach ($_SESSION as $key => $value){
unset($_SESSION[$key]);
}
session_decode($currentSession);
return $sessionVariables;
}