Question

我希望有人可以提供帮助。我创建了这个存储过程来从不同的表中提取一些信息，当我调整它时，我得到了很多重复，我想知道是否有一种方法对它进行排序？

use ICA
if exists(
    select *
    from INFORMATION_SCHEMA.ROUTINES
    where SPECIFIC_SCHEMA = N'ICASchema'
    and SPECIFIC_NAME = N'candidateOffer'
    )
    drop procedure ICASchema.candidateOffer
go

create procedure ICASchema.candidateOffer @candidateID INT
    as
begin

select c.CandidateID,c.CandidateName, ca.CourseID, co.CourseName, o.OfferID, ot.OfferTypePoints
    from [ICASchema].[tblCandidate] c 
    join [ICASchema].[tblCandidateOffer] o on c.CandidateID = o.CandidateID
    join [ICASchema].[tblOffer] ot on o.offerID = ot.OfferType
    join [ICASchema].[tblCandidateApplication] ca on ca.CourseID = ca.CourseID
    join [ICASchema].[tblCourse] co on co.CourseName = co.CourseName
    where c.CandidateID = @candidateID
    --ORDER BY co.CourseName
    GROUP BY  co.CourseName, c.CandidateID,c.CandidateName, ca.CourseID, o.OfferID, ot.OfferTypePoints
end
go

由于

格雷厄姆

Answer 1

试试这个：

select * from (select distinct c.CandidateID,c.CandidateName, ca.CourseID, co.CourseName, o.OfferID, ot.OfferTypePoints
    from [ICASchema].[tblCandidate] c 
    join [ICASchema].[tblCandidateOffer] o on c.CandidateID = o.CandidateID
    join [ICASchema].[tblOffer] ot on o.offerID = ot.OfferType
    join [ICASchema].[tblCandidateApplication] ca on ca.CourseID = ca.CourseID
    join [ICASchema].[tblCourse] co on co.CourseName = co.CourseName
    where c.CandidateID = @candidateID

    GROUP BY  co.CourseName, c.CandidateID,c.CandidateName, ca.CourseID, o.OfferID, ot.OfferTypePoints) tablealias order by CourseName

Answer 2

以下示例用于创建简单的Proc_GetAllUsers存储过程。这将解决您的重复问题。

如果出现{DIG PROCEDURE Proc_GetAllUsers GO

CREATE PROCEDURE Proc_GetAllUsers（）开始

- 你的SQL查询选择* FROM用户;

结束

开始

Answer 3

这是可行的解决方案。

[code] SELECT c.CandidateID，c.CandidateName，ICASchema.tblOffer.OfferTypePoints，ICASchema.tblCourse.CourseName 来自ICASchema.tblCandidate AS c INNER JOIN ICASchema.tblCandidateOffer ON c.CandidateID = ICASchema.tblCandidateOffer.CandidateID INNER JOIN ICASchema.tblOffer ON ICASchema.tblCandidateOffer.CandidateOfferID = ICASchema.tblOffer.OfferID INNER JOIN ICASchema.tblCourse on ICASchema.tblOffer.OfferID = ICASchema.tblCourse.OfferTypeID WHERE（c.CandidateID ='3'） [/代码]

MySQL存储过程重复问题

3 个答案: