Question

我有一个ArrayList＆gt;＆gt;它包含某些键值条目。如： -

    ArrayList<HashMap<String, String>> mList = new ArrayList<HashMap<String,String>>();
    HashMap<String,String> map = new HashMap<String,String>();
    map.put("NewId", newId);
    map.put("Title", title);
    map.put("Description", description);
    mList.add(map);

MyList myList = new MyList(mList);

itemsAdapter = new LazyAdapter(myContext, myList);

            newList.setAdapter(itemsAdapter);

“NewId”对于多个条目可能类似。

我也有一系列颜色： -

String[] colors = new String[]{"#1F1A17", "#62934D", "#F9B03F", "#7959BC", "#74B8DE", "#E65641", "#7CC8BB", "#D7CE5D", "#D6BE95", "#B694D1"};

我想要一个mew组，其中所有条目都有相同的“NewId”，并为它们分配第一种颜色，其他条目与下一个类似的“NewId”和第二种颜色等等，直到前10个相同“NewId”的项目得到分配各自的颜色。

例如： - 分组前

NewId  Title  Description
 101   title1  des1
 102   title2  des2
 103   title3  des3 
 101   title4  des4
 102   title5  des5
 103   title6  des6

分组后，

NewId  Title  Description
 101   title1  des1  ------> color1
 101   title4  des4  ------> color1
 102   title2  des2  ------> color2
 102   title5  des5  ------> color2
 103   title3  des3  ------> color3
 103   title6  des6  ------> color3

我还做了什么： -

    public class MyList {

        private ArrayList<HashMap<String, String>> list = new ArrayList<>();

public MyList(ArrayList<HashMap<String, String>> mylist)
    {
        this.list = mylist;
    }


        public boolean add(HashMap<String, String> map) {
            return list.add(map);
        }

        public void setColor(String newId, String color) {
            for (HashMap<String, String> m : list)
                if (m.containsKey(newId))
                    m.put("color", color);
        }

        public String getGroupKey(String key, int i) {      
            ArrayList<String> uniqeList = getUniqKeyList(key);
            Collections.sort(uniqeList);
            return uniqeList.get(i);
        }

        public ArrayList<String> getUniqKeyList(String key){
            ArrayList<String> l = new ArrayList<>();
            for (HashMap<String, String> m : list)
                if(!l.contains(m.get(key)))
                    l.add(m.get(key));
            return l;
        }
    }

    public static void main(String[] args) throws Exception {
            MyList myList = new MyList();
            HashMap<String,String> map = new HashMap<String,String>();
            map.put("NewId", newId);
            map.put("Title", title);
            map.put("Description", description);
            myList.add(map);

            String[] colors = new String[]{"#1F1A17", "#62934D","#B694D1"};

            int i=0;
            while (true) {
                        if(i == colors.length) 
                                break;
                String s =  myList.getGroupKey("NewId", i);
                if(s == null)
                    break;
                else 
                    myList.setColor(s, colors[i++]);
            }       
        }

itemsAdapter = new LazyAdapter(myContext, myList);

但是我收到了一个错误： -

04-24 04:57:49.993: E/AndroidRuntime(1882): Caused by: java.lang.IndexOutOfBoundsException: Invalid index 4, size is 4
04-24 04:57:49.993: E/AndroidRuntime(1882):     at java.util.ArrayList.throwIndexOutOfBoundsException(ArrayList.java:251)
04-24 04:57:49.993: E/AndroidRuntime(1882):     at java.util.ArrayList.get(ArrayList.java:304)
04-24 04:57:49.993: E/AndroidRuntime(1882):     at Utility.MyList.getGroupKey(MyList.java:58)

Answer 1

try...

  while (true) {
                        if(i >= colors.length) 
                                break;
                String s =  myList.getGroupKey("NewId", i);
                if(s == null)
                    break;
                else 
                    myList.setColor(s, colors[i++]);
            }

对ArrayList进行分组<hashmap <string，string>＆gt;根据值，并相对于排序键</hashmap <string，string>添加另一个值

1 个答案: