Question

我在DB中有3个表： task_estimation_fields：

CREATE TABLE `task_estimation_fields` (
  `id` int(11) NOT NULL AUTO_INCREMENT,
  `name` varchar(45) NOT NULL,
  PRIMARY KEY (`id`),
  UNIQUE KEY `name_UNIQUE` (`name`)
) ENGINE=InnoDB;

task_estimations：

CREATE TABLE `task_estimations` (
  `id` int(11) NOT NULL AUTO_INCREMENT,
  `task_id` int(11) NOT NULL,
  `task_estimation_field_id` int(11) NOT NULL,
  `description` blob,
  `summary` blob,
  `effort` int(11) NOT NULL,
  `created_at` datetime NOT NULL,
  `created_by` int(11) NOT NULL,
  PRIMARY KEY (`id`),
  KEY `g1` (`task_id`),
  KEY `g2` (`created_by`),
  KEY `g3` (`task_estimation_field_id`),
  CONSTRAINT `g1` FOREIGN KEY (`task_id`) REFERENCES `tasks` (`id`) ON DELETE NO ACTION         ON UPDATE NO ACTION,
  CONSTRAINT `g2` FOREIGN KEY (`created_by`) REFERENCES `users` (`id`) ON DELETE NO ACTION ON UPDATE NO ACTION,
  CONSTRAINT `g3` FOREIGN KEY (`task_estimation_field_id`) REFERENCES     `task_estimation_fields` (`id`) ON DELETE NO ACTION ON UPDATE NO ACTION
) ENGINE=InnoDB;

任务：

CREATE TABLE `tasks` (
  `id` int(11) NOT NULL AUTO_INCREMENT,
  `assignee_id` int(11) NOT NULL,
  `status_id` int(11) NOT NULL,
  `prioryty_id` int(11) NOT NULL,
  `title` varchar(45) NOT NULL,
  `description` longblob,
  PRIMARY KEY (`id`)
) ENGINE=InnoDB;

使用以下命令从现有数据库生成的实体文件：

$ php app/console doctrine:mapping:import --force AcmeBlogBundle xml
$ php app/console doctrine:mapping:convert annotation ./src
$ php app/console doctrine:generate:entities AcmeBlogBundle

我希望获得此查询的结果：

SELECT * FROM task_estimation_fields tef LEFT JOIN task_estimations te ON (tef.id = te.task_estimation_field_id AND te.task_id = 1)

我正在使用symfony 2.4.3并且我已经生成了以下代码：

$estimations = $this->getDoctrine()
                ->getManager()
                ->createQueryBuilder()
                ->select('tef, te')
                ->from('SynapthsisSpecBundle:TaskEstimationFields', 'tef')
                ->leftJoin('SynapthsisSpecBundle:TaskEstimations', 'te', 'WITH', 'tef.id = te.task_estimation_field_id AND te.task_id = :id')
                ->setParameter('id', $id)
                ->getQuery()
                ->getResult();

问题是我遇到了以下错误：

[Semantical Error] line 0, col 133 near 'task_estimation_field_id': Error: Class Synapthsis\SpecBundle\Entity\TaskEstimations has no field or association named task_estimation_field_id

这就是说，在实体中没有这样的领域，但有：

/**
 * @var \Synapthsis\SpecBundle\Entity\TaskEstimationFields
 *
 * @ORM\ManyToOne(targetEntity="Synapthsis\SpecBundle\Entity\TaskEstimationFields")
 * @ORM\JoinColumns({
 *   @ORM\JoinColumn(name="task_estimation_field_id", referencedColumnName="id")
 * })
 */
private $taskEstimationField;

涵盖了这种关系。

我从queryBuilder中删除了关系：

$estimations = $this->getDoctrine()
            ->getManager()
            ->createQueryBuilder()
            ->select('tef, te')
            ->from('SynapthsisSpecBundle:TaskEstimationFields', 'tef')
            ->leftJoin('SynapthsisSpecBundle:TaskEstimations', 'te', 'WITH', 'te.task_id = :id')
            ->setParameter('id', $id)
            ->getQuery()
            ->getResult();

我收到了：

[Semantical Error] line 0, col 124 near 'task_id = :i': Error: Class Synapthsis\SpecBundle\Entity\TaskEstimations has no field or association named task_id

这也是事实，因为在实体中它包含在：

/**
 * @var \Synapthsis\SpecBundle\Entity\Tasks
 *
 * @ORM\ManyToOne(targetEntity="Synapthsis\SpecBundle\Entity\Tasks")
 * @ORM\JoinColumns({
 *   @ORM\JoinColumn(name="task_id", referencedColumnName="id")
 * })
 */
private $task;

如何获得我需要的结果？如何在树枝上打印这些结果？

Answer 1

在DQL查询中，您需要使用关联名称而不是列名称。

在您的情况下，您需要使用te.taskEstimationField代替te.task_estimation_field_id和te.task代替te.task_id。

Symfony 2 Doctrine LEFT JOIN

1 个答案: