尽管我努力改变按钮的颜色,并且到处读取如何操作,但我的代码仍然没有产生预期的效果。如何更改JButton的颜色 什么时候点击?
public void generateButtons
{
//Global field
firstBoard = new JButton[9][9];
for(int x = 0; x < firstBoard.length; x++)
{
for(int y = 0; y < firstBoard[0].length; y++)
{
firstBoard[x][y] = new JButton();
firstBoard[x][y].setActionCommand("0|" + (x + (firstBoard.length * y)));
firstBoard[x][y].addActionListener(this);
//firstBoardPanel.add(firstBoard[x][y]);
}
}
}
@Override
public void actionPerformed(ActionEvent e)
{
if(e.getSource() instanceof JButton )
{
System.out.println(parseActionCommand(((JButton)e.getSource()).getActionCommand()));
((JButton)e.getSource()).setBackground(Color.BLUE);
((JButton)e.getSource()).setContentAreaFilled(false);
((JButton)e.getSource()).setOpaque(true);
}
}
答案 0 :(得分:1)
尝试重新绘制包含该按钮的容器。
button.getParent().validate();
button.getParent().repaint();
答案 1 :(得分:1)
这不是一个答案,而是一个测试Mac OS外观和感觉与Nimbus之间差异的扩展测试用例,在Windows操作系统上运行时可以 < / p>
看来,这成了答案......
请尝试以...开头
import java.awt.BorderLayout;
import java.awt.Color;
import java.awt.EventQueue;
import java.awt.GridLayout;
import java.awt.event.ActionEvent;
import java.awt.event.ActionListener;
import javax.swing.JButton;
import javax.swing.JFrame;
import javax.swing.JPanel;
import javax.swing.UIManager;
import javax.swing.UIManager.LookAndFeelInfo;
import javax.swing.UnsupportedLookAndFeelException;
public class ChangeButton {
public static void main(String[] args) {
new ChangeButton();
}
public ChangeButton() {
EventQueue.invokeLater(new Runnable() {
@Override
public void run() {
try {
UIManager.setLookAndFeel(UIManager.getSystemLookAndFeelClassName());
} catch (ClassNotFoundException | InstantiationException | IllegalAccessException | UnsupportedLookAndFeelException ex) {
}
JFrame frame = new JFrame("Testing");
frame.setDefaultCloseOperation(JFrame.EXIT_ON_CLOSE);
frame.setLayout(new BorderLayout());
frame.add(new TestPane());
frame.pack();
frame.setLocationRelativeTo(null);
frame.setVisible(true);
}
});
}
public class TestPane extends JPanel implements ActionListener {
private final JButton[][] firstBoard;
public TestPane() {
setLayout(new GridLayout(9, 9));
firstBoard = new JButton[9][9];
for (int x = 0; x < firstBoard.length; x++) {
for (int y = 0; y < firstBoard[0].length; y++) {
firstBoard[x][y] = new JButton();
firstBoard[x][y].setActionCommand("0|" + (x + (firstBoard.length * y)));
firstBoard[x][y].addActionListener(this);
add(firstBoard[x][y]);
}
}
}
public void actionPerformed(ActionEvent e) {
if (e.getSource() instanceof JButton) {
System.out.println((((JButton) e.getSource()).getActionCommand()));
((JButton) e.getSource()).setBackground(Color.BLUE);
((JButton) e.getSource()).setContentAreaFilled(false);
((JButton) e.getSource()).setOpaque(true);
}
}
}
}
然后用{...}替换UIManager.setLookAndFeel(UIManager.getSystemLookAndFeelClassName());
。
for (LookAndFeelInfo info : UIManager.getInstalledLookAndFeels()) {
if ("Nimbus".equals(info.getName())) {
UIManager.setLookAndFeel(info.getClassName());
break;
}
}
再试一次
答案 2 :(得分:-1)
不要直接使用你需要的e.getSource()
来引用它,然后使用它:
示例:强>
ublic void actionPerformed(ActionEvent e)
{
Object ob = e.getSource();
if(ob instanceof JButton )
{
System.out.println(parseActionCommand(((JButton)e.getSource()).getActionCommand()));
JButton button = ((JButton)ob);
button.setBackground(Color.BLUE);
button.setContentAreaFilled(false);
button.setOpaque(true);
}