我正在尝试为我的结果创建过滤器,该过滤器会从html表单中获取多个值。 这个当前的设置给了我这样的网址/?language = French& language = German但是结果不会显示法语和德语记录而只显示法语。此外,添加新的过滤条件,例如" level" /?language = French& level =初学者也不起作用。
请有人帮忙并指出我正确的方向吗?
感谢 sikor
我的表格如下:
RESOURCES_LANGUAGE = (('English', 'English'),
('Spanish', 'Spanish'),
('French', 'French'),
('German', 'German'))
RESOURCES_LEVEL = (('Beginner', 'Beginner'),
('Intermediate', 'Intermediate'),
('Advanced', 'Advanced'))
SORTBY = (('likes', 'Likes'),
('name', 'Name'),
('latest', 'Latest'))
class FiltersAndSortingForm(forms.Form):
language = forms.MultipleChoiceField(required=False, label='Language', widget=forms.CheckboxSelectMultiple, choices=RESOURCES_LANGUAGE)
level = forms.MultipleChoiceField(required=False, label='Level', widget=forms.CheckboxSelectMultiple, choices=RESOURCES_LEVEL)
provider = forms.ModelMultipleChoiceField(queryset=Provider.objects.all().order_by('name'), label='Provider', required=False,)
sortby = forms.MultipleChoiceField(required=False, label='Sort by', widget=forms.CheckboxSelectMultiple, choices=SORTBY)
我的观点:
def resources(request):
if request.GET:
language = request.GET.get('language', '')
level = request.GET.get('level', '')
provider = request.GET.get('provider', '')
sortby = request.GET.get('sortby', '')
if sortby == 'name':
orderby = 'name'
elif sortby == 'latest':
orderby = '-dt_added'
elif sortby == 'likes':
orderby = '-facebook_likes'
else:
orderby = '-facebook_likes'
qset = (
Q(language=language)
# &
# Q(level=level)
)
resources = Resource.objects.filter(inactive=0).filter(qset).order_by(orderby)
form = FiltersAndSortingForm()
else:
form = FiltersAndSortingForm()
resources = Resource.objects.filter(inactive=0).order_by('-facebook_likes')
答案 0 :(得分:1)
好的,最后看完这个帖子后django dynamically filtering with q objects我得到了这样的工作。也许这不是最干净的方式,但似乎正在做这项工作。除非有人能提出更好的解决方案吗?
感谢 -s
def resources(request):
if request.GET:
type = request.GET.getlist('type', '')
language = request.GET.getlist('language', '')
level = request.GET.getlist('level', '')
provider = request.GET.getlist('provider', '')
sortby = request.GET.get('sortby', '')
if sortby == 'name':
orderby = 'name'
elif sortby == 'latest':
orderby = '-dt_added'
elif sortby == 'likes':
orderby = '-facebook_likes'
else:
orderby = '-facebook_likes'
qset_type = Q() # Create an empty Q object to start with
for x in type:
qset_type |= Q(provider__tags__name=x) # 'or' the Q objects together
qset_language = Q()
for x in language:
qset_language |= Q(language=x)
qset_level = Q()
for x in level:
qset_level |= Q(level=x)
qset_provider = Q()
for x in provider:
qset_provider |= Q(provider=x)
qset = qset_language & qset_level & qset_type & qset_provider
resources = Resource.objects.filter(inactive=0).filter(qset).order_by(orderby)
form = FiltersAndSortingForm()
else:
form = FiltersAndSortingForm()
resources = Resource.objects.filter(inactive=0).order_by('-facebook_likes')
答案 1 :(得分:0)
我没有看到在qset中添加其他标准,这就是为什么过滤不适用于这些参数的原因。另外,我建议您使用字典作为搜索条件,然后将其解压缩。请查看此问题以获取详细说明Django: How do I use a string as the keyword in a Q() statement?。如果您需要任何澄清,请告诉我。