触发器不会工作

时间:2014-05-05 00:49:58

标签: oracle plsql oracle11g syntax-error

我创建了Trigger,它检查广告表中的付款并且应该更新另一个表(customer_account)是否有人知道bug在哪里?

   CREATE OR REPLACE TRIGGER Payment_check
   after UPDATE ON Ads
   FOR EACH ROW
   BEGIN
   IF NEW.Pay_done==('y'||'Y')THEN
   UPDATE customer_account SET customer_account.Plcd_ads = NEW.Ad_id
   WHERE customer_account.C_id = NEW.Customer;
   ELSE
   UPDATE customer_account SET customer_account.Pend_ads = NEW.Ad_id 
   WHERE customer_account.C_id = NEW.Customer;
   END IF;
   END;


 //////bug

 Error at line 7: PLS-00103: Encountered the symbol "." when expecting one of the                                                                following:

  mod  
  continue current sql execute forall merge
 pipe purge
 The symbol "" was substituted for "." to continue.

5. IF NEW.Pay_done==('y'||'Y')THEN
6. UPDATE customer_account SET customer_account.Plcd_ads = NEW.Ad_id
7. WHERE customer_account.C_id = NEW.Customer;
8. ELSE
9. UPDATE customer_account SET customer_account.Pend_ads = NEW.Ad_id 

2 个答案:

答案 0 :(得分:5)

还请提供表格创建语句,以便轻松重现您的错误。

以下是两个可能的问题。如果这不能解决错误,请更改这些并更新问题。

1)新运营商需要以“:”为前缀

2)检查pay_done标志的条件可能只是“上限(:NEW.Pay_done)='Y'”

CREATE OR REPLACE TRIGGER Payment_check
AFTER UPDATE
   ON Ads
FOR EACH ROW
BEGIN
   IF upper(:NEW.Pay_done) = 'Y' THEN
       UPDATE customer_account SET customer_account.Plcd_ads = :NEW.Ad_id
       WHERE customer_account.C_id = NEW.Customer;
       ELSE
       UPDATE customer_account SET customer_account.Pend_ads = :NEW.Ad_id 
       WHERE customer_account.C_id = :NEW.Customer;
   END IF;
END;

答案 1 :(得分:0)

Rajesh Chamarthi感谢您的回复,您的代码也无法正常工作,但有助于找到我的朋友。在新值和

之前缺少的冒号
     IF NEW.Pay_done==('y'||'Y')THEN
     changed for
     IF NEW.Pay_done=('y'||'Y')THEN

工作!

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