Question

我连续运行两个awk命令，根据多个分隔符分解字符串。我想知道它们是否可以组合成一个命令。

输入数据（jot -w "some string, this is number " 10）：

some string, this is number 1
some string, this is number 2
some string, this is number 3
some string, this is number 4
some string, this is number 5
some string, this is number 6
some string, this is number 7
some string, this is number 8
some string, this is number 9
some string, this is number 10

这只是示例数据，但我希望能够先根据逗号分割字符串，然后从第二部分中提取数字（第四个字）。实际上，字符串第一部分中的空格数可能会有所不同，即以下是有效输入：

some string, this is number 1
some string with more spaces, this is number 2

以下命令正常工作：

$ jot -w "some string, this is number " 10 | awk -F ',' '{print $2}' | awk -F ' ' '{print $4}'
1
2
3
4
5
6
7
8
9
10

有没有简单的方法将这两个命令合并为一个？

Answer 1

split()功能可以让你这样做：

awk '{split($0,a,",");split(a[2],b," ");print b[4];}'

Answer 2

您可以使用NF轻松打印最后一列

jot -w "some string, this is number " 10 |awk '{print $NF}'

或者按照你的想法，将两个awk合并为一个。

jot -w "some string, this is number " 10  |awk '{l=split($2,a,OFS);print a[l]}' FS=","

Answer 3

要解决您描述的问题：

$ cat file
some string, this is number 1
some string with more spaces, this is number 2

$ awk -F, '{n=split($NF,a,/ /); print a[n]}' file
1
2

或者如果你喜欢高尔夫：

$ awk -F, '{print a[split($NF,a,/ /)]}' file
1
2

但很明显，您指定的输入会起作用：

$ awk '{print $NF}' file
1
2

以及其他各种解决方案。

将多个awk命令与不同的分隔符组合在一起

3 个答案: