Question

我有一个像

这样的字符串

"<Canvas Background="#FF00FFFF" Name="Page_1" Width="1200" Height="900" ><TextBlock Name="PageTitle" /></Canvas><Canvas Background="#FF00FFFF" Name="Page_2" Width="1200" Height="900"><TextBlock Name="PageTitle" /></Canvas>"

我想将此字符串拆分为类似

的数组

[< Canvas Background="#FF00FFFF" Name="Page_1" Width="1200" Height="900" >< TextBlock Name="PageTitle" />< /Canvas>],

[< Canvas Background="#FF00FFFF" Name="Page_2" Width="1200" Height="900">< TextBlock Name="PageTitle" />< /Canvas>]

但是当我使用

时

objectsAsStrings = contents.Split(new string[] { "/Canvas><Canvas" }, StringSplitOptions.None);

我删除了分隔符，我不想要的东西。如何拆分字符串BETWEEN“/ Canvas”和“＆lt; Canvas”？

Answer 1

试试这个

string mailstring = "<Canvas Background='#FF00FFFF' Name='Page_1' Width='1200' Height='900' ><TextBlock Name='PageTitle' /></Canvas><Canvas Background='#FF00FFFF' Name='Page_2' Width='1200' Height='900'<TextBlock Name='PageTitle' /></Canvas>";
            string splitor = "</Canvas>";
            string[] substrings = mailstring.Split(new string[] { splitor }, StringSplitOptions.None);
            string part1 = substrings[0] + splitor;
            string part2 = substrings[1] + splitor;

Answer 2

或者，您可以像这样使用XML解析器：

string xml = "<Canvas Background=\"#FF00FFFF\" Name=\"Page_1\" Width=\"1200\" Height=\"900\" ><TextBlock Name=\"PageTitle\" /></Canvas><Canvas Background=\"#FF00FFFF\" Name=\"Page_2\" Width=\"1200\" Height=\"900\"><TextBlock Name=\"PageTitle\" /></Canvas>";
xml = "<Outer>" + xml + "</Outer>";
XDocument doc = XDocument.Parse(xml);
string[] array = doc.Descendants("Canvas").Select(item => item.ToString(SaveOptions.DisableFormatting)).ToArray();

然后array[]将包含您想要的内容。这可能更普遍有用。

这使您有机会进行更高级别的解析（控制台应用程序代码）：

string xml = "<Canvas Background=\"#FF00FFFF\" Name=\"Page_1\" Width=\"1200\" Height=\"900\" ><TextBlock Name=\"PageTitle1\" /></Canvas><Canvas Background=\"#FF00FFFF\" Name=\"Page_2\" Width=\"1200\" Height=\"900\"><TextBlock Name=\"PageTitle2\" /></Canvas>";
xml = "<Outer>" + xml + "</Outer>";
XDocument doc = XDocument.Parse(xml);

var items = from item in doc.Descendants("Canvas") select new
{
    Background    = (string) item.Attribute("Background"),
    Name          = (string) item.Attribute("Name"),
    Width         = (int)    item.Attribute("Width"),
    Height        = (int)    item.Attribute("Height"),
    TextBlockName = (string) item.Element("TextBlock").Attribute("Name")
};

foreach (var item in items)
{
    Console.WriteLine
    (
        "Background = {0}\n" +
        "Name = {1}\n" +
        "Width = {2}\n" +
        "Height = {3}\n" +
        "TextBlockName = {4}\n",
        item.Background,
        item.Name,
        item.Width,
        item.Height,
        item.TextBlockName
    );
}

此代码的输出为：

Background = #FF00FFFF
Name = Page_1
Width = 1200
Height = 900
TextBlockName = PageTitle1

Background = #FF00FFFF
Name = Page_2
Width = 1200
Height = 900
TextBlockName = PageTitle2

Answer 3

使用Split，然后迭代数组并将"<Canvas"插入除第一项之外的所有项目的开头，将"/Canvas>"追加到除了{1}}之外的所有项目的末尾最后。

contents = "<Canvas Background=\"#FF00FFFF\" Name=\"Page_1\" Width=\"1200\" Height=\"900\" ><TextBlock Name=\"PageTitle\" /></Canvas><Canvas Background=\"#FF00FFFF\" Name=\"Page_2\" Width=\"1200\" Height=\"900\"><TextBlock Name=\"PageTitle\" /></Canvas>";
objectsAsStrings = contents.Split(new string[] { "/Canvas><Canvas" }, StringSplitOptions.None);

for(var i = 0; i < objectsAsStrings.Length; i++)
{
    if( 0 < i) objectsAsStrings[i] = "<Canvas" + objectsAsStrings[i];
    if( i < objectsAsStrings.Length-1) objectsAsStrings[i] = objectsAsStrings[i] + "/Canvas>";
}

Answer 4

@Najib是对的

但是你永远不知道你会得到多少个子串......... 因此

而不是

string part1 = substrings[0] + splitor;
string part2 = substrings[1] + splitor;

试试这个

for(int i=0;i<substrings.Lenght;i++)
{
    substrings[i]+=splitor;
}

Answer 5

不确定使用linq进行字符串操作是否合适，但这是另一种方法：

var contents = "<Canvas Background=\"#FF00FFFF\" Name=\"Page_1\" Width=\"1200\" Height=\"900\" ><TextBlock Name=\"PageTitle\" /></Canvas><Canvas Background=\"#FF00FFFF\" Name=\"Page_2\" Width=\"1200\" Height=\"900\"><TextBlock Name=\"PageTitle\" /></Canvas>";
var a = from word in contents.Split(new string[] { "/Canvas><Canvas" }, StringSplitOptions.None) select word;
var b = from word in a where word == a.First() select word.Replace("<Canvas","");
var c = from word in a where word == a.Last() select word.Replace("/Canvas>","");
var d = from word in a where word != a.Last() && word != a.First() select word;
var result = b.Concat(d).Concat(c).Select(f => "<Canvas" + f + "/Canvas>");`

拆分2个子字符串之间的字符串，而不删除分隔符

5 个答案: