Question

我必须按照其中提供的日期对对象列表进行排序。我最初的想法是使用开关盒。但这意味着最多31个案例。这是我使用的代码：

if (e.getSource() == btnSalesPerDay)
        {
            //int i =0;
            SalesTextArea.setText("");

            Object[] possibilities = {"1", "2", "3", "4", "5", "6", "7", "8", "9", "10", "11", "12", "13", "14", "15", "16", "17", "18", "19", "20", "21", "22", "23", "24", "25", "26", "27", "28", "29", "30", "31"};
            String dayOption = (String)JOptionPane.showInputDialog(frame,"Pick a day you wish to display the records for : ", "Catagory pick", JOptionPane.PLAIN_MESSAGE, null, possibilities,"ham");

            switch(dayOption)
            {
            case 1:
                if(salesdata[i].day == 1)
                {
                    int i =0;
                    while (salesdata != null)
                    {
                        SalesTextArea.insert("\t" + salesdata[i].totalPrice, 0);
                        SalesTextArea.insert("\t" + salesdata[i].year, 0);
                        SalesTextArea.insert("\t" + salesdata[i].month, 0);
                        SalesTextArea.insert("\t" + salesdata[i].day, 0);
                        SalesTextArea.insert("\t" + salesdata[i].customerName, 0);
                        SalesTextArea.insert("\t" + salesdata[i].salesNo, 0);
                        SalesTextArea.insert("\n", 0);
                        i++;
                    }
                }
                break;
case 2:
                if(salesdata[i].day == 2)
                {
                    int i =0;
                    while (salesdata != null)
                    {
                        SalesTextArea.insert("\t" + salesdata[i].totalPrice, 0);
                        SalesTextArea.insert("\t" + salesdata[i].year, 0);
                        SalesTextArea.insert("\t" + salesdata[i].month, 0);
                        SalesTextArea.insert("\t" + salesdata[i].day, 0);
                        SalesTextArea.insert("\t" + salesdata[i].customerName, 0);
                        SalesTextArea.insert("\t" + salesdata[i].salesNo, 0);
                        SalesTextArea.insert("\n", 0);
                        i++;
                    }
                }
                break;

最多可达31例.. 我的问题是......有更简单的方法吗？什么是最有效的方法呢？

谢谢：）

Answer 1

你只需要一个循环：

String dayOption = (String)JOptionPane.showInputDialog(frame,"Pick a day you wish to display the records for : ", "Catagory pick", JOptionPane.PLAIN_MESSAGE, null, possibilities,"ham");

int chosenDay = Integer.parseInt(dayOption);
for (SalesData item : array) {
    if (item.day == chosenDay) {
        // ...
    }
}

在这种情况下，是否有更容易/更短的开关盒代码？

1 个答案: